-2
即使满足条件,控件也不退出循环。如果recipientEmailAddressList
大小大于1,并且即使第一次尝试本身为foundEmail
,它也不会退出循环。这个while循环有什么问题? 请告诉我下面的代码有什么问题。即使条件满足,控制也不退出循环?
do {
if(reTry>=1){
Thread.sleep(15000);
}
response = RestAssured.given().accept("application/json").get(url);
String responseBody = response.asString();
JsonPath jsonPath = new JsonPath(responseBody);
List<String> recipientEmailAddressList = jsonPath.get("recipientEmail");
System.out.println("receipeinet email list size "+recipientEmailAddressList.size());
for (int i=0;i<recipientEmailAddressList.size();i++) {
if(recipientEmailAddressList.get(i).equalsIgnoreCase(studentEmail)){
System.out.println(recipientEmailAddressList.get(i));
List<Object> rawRequest = jsonPath.get("rawRequest");
JsonPath rawRequestJsonPath = new JsonPath(rawRequest.get(0).toString());
String claimURL=rawRequestJsonPath.getString("parameters.claim_url");
NewTempData.storedata(6, 1, claimURL);
System.out.println("Credential Claim URL "+claimURL);
foundEmail = true;
}else{
foundEmail = false;
}
}
reTry++;
} while (reTry < 30 &!foundEmail);
if(foundEmail){
return true;
}
对于我第一次尝试用&&只有但当左手条件真正的(!foundEmail)当我得到的响应它不退出循环继续。所以尝试与&但这个alos不能解决这个问题。 –
@ CraigR8806当操作数是布尔值时,单个'&'*确实*表示比较,当左侧是'false'时它不会快捷。即评估'false&2> 1'的右侧,而'false && 2> 1'则不是这种情况 – NickL