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我想从我的数据库使用ajax和php获取数据,但每当我尝试获取数据时,都会收到ajax错误消息。这里是我的代码:PHP将数据发送回AJAX
HTML
这里是我的代码,我请求PHP文件。
<body>
<div id="wrapper">
<h2>Coffe Shop</h2>
<p class="bold">Drink orders:</p>
<ul class="orders">
</ul>
<p class="bold">Add an order:</p>
<p>Drink: <input type="text" id="name"/><input type="submit" id="submit"/></p>
<button id="refresh">CLICK ME</button>
</div>
<script>
$(function(){
$("#refresh").on("click", function() {
$.ajax({
type: "GET",
url: "data.php",
dataType: "json",
success: function(names){
$.each(names, function(name){
alert(name);
});
},
error: function(){
alert("error");
}
});
});
});
</script>
</body>
PHP
这是我的PHP文件
<?php
$conn = mysqli_connect("localhost:8080", "root", "", "test1")
or die("Error with connection");
$sql = "SELECT ime FROM users;";
$result = mysqli_query($conn, $sql);
$row = mysqli_fetch_array($result);
$names = array();
while($row){
$name = array(
"name"=> $row['ime']
);
$names[] = $name;
}
echo json_encode($names);
有什么错误? –