2010-11-21 46 views
1

我有一个带有复选框的数据网格,它调用一个名为checkbox_CheckedChanged的例程。到现在为止还挺好。我设法弄清楚了dataview中另一列的值,这使我能够确定我正在处理的行的id。vb.net SQL查询在SQL服务器中工作,但在复选框中调用时不起作用

我试图让它改变定义复选框的初始值的列的值,但是我写的SQL在vb.net调用时不起作用 - 它在输入时工作然而,手动到SQL服务器。

这里是我的背后代码:

Public Sub checkbox_CheckedChanged(ByVal sender As Object, ByVal e As EventArgs) 'Handles checkbox.CheckedChanged 
    Dim connectionString As String = WebConfigurationManager.ConnectionStrings("edinsec").ConnectionString 


    Dim box As CheckBox = DirectCast(sender, CheckBox) 
    Dim tblcell As TableCell = CType(box.Parent, TableCell) 
    Dim dgRow As GridViewRow = CType(tblcell.Parent, GridViewRow) 

    Dim msgId As Integer = unreadMessages.Rows(dgRow.DataItemIndex).Cells(0).Text 

    Dim insertSQL As String 

    If box.Checked = True Then 
    insertSQL = "UPDATE messages" 
    insertSQL &= "SET readit = 0" 
    insertSQL &= "WHERE msgid = @msgId" 
    Else 
    insertSQL = "UPDATE messages" 
    insertSQL &= "SET readit = 1" 
    insertSQL &= "WHERE msgid = @msgId" 
    End If 

    Using con As New SqlConnection(connectionString) 
    Dim cmd As New SqlCommand(insertSQL, con) 
    cmd.Parameters.AddWithValue("@msgId", msgId) 
    Try 
     con.Open() 
     cmd.ExecuteNonQuery() 
    Catch Err As SqlException 
     MsgBox("Error", 65584, "Insertion Error") 
    End Try 
    con.Close() 
    End Using 

End Sub 

的想法是,点击后,该复选框将在数据库中,以它的反面翻转“readit的价值。它不断跳转到SqlException,所以我看到了错误消息。

的复选框的ASPX代码是这样的:

  <asp:TemplateField HeaderText="readit" SortExpression="readit"> 
    <ItemTemplate> 
     <asp:CheckBox ID="CheckBox1" runat="server" AutoPostBack="true" OnCheckedChanged="checkbox_CheckedChanged" Checked='<%# Bind("readit") %>' 
      Enabled="true" /> 
    </ItemTemplate> 
    <EditItemTemplate> 
     <asp:CheckBox ID="CheckBox1" runat="server" AutoPostBack="true" OnCheckedChanged="checkbox_CheckedChanged" Checked='<%# Bind("readit") %>' /> 
    </EditItemTemplate> 
     </asp:TemplateField> 

任何帮助将非常感激。 Visual Studio(2008)给出了在这种情况下对SQL错误的反馈,这非常令人生气。

回答

1

您需要在您的更新语句添加一些空格:messagesreadit = 0/1后,我已经添加空间

If box.Checked = True Then 
     insertSQL = "UPDATE messages " 
     insertSQL &= "SET readit = 0 " 
     insertSQL &= "WHERE msgid = @msgId" 
    Else 
     insertSQL = "UPDATE messages " 
     insertSQL &= "SET readit = 1 " 
     insertSQL &= "WHERE msgid = @msgId" 
    End If 

通知。否则您的陈述将为UPDATE messagesSET ...,这在SSMS中也不起作用。

+0

克劳斯 - 非常感谢,这使得SQL运行。麻烦的是,我必须点击复选框两次才能更改为“粘贴”...编辑:我只是有逻辑错误的方式... noob错误:) – melat0nin 2010-11-22 10:53:40

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