2016-03-03 135 views
0

比方说,我有一个正在运行的服务的API,响应就像一个网址:REST API服务:如何通过PHP curl正确调用它?

http://example.com/param/1 

这是对GET和POST动词担任。 Param = 1是参数

如何正确执行curl请求以传递参数(POST)?

如果我浏览:http://example.com/param/1 我会回来预期的响应(GET)

但如果我这样做,这是行不通的:

$service_url = 'http://example.com/'; 
$curl = curl_init($service_url); 
$curl_post_data = array('param'=>1); 

curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($curl, CURLOPT_POST, true); 
curl_setopt($curl, CURLOPT_POSTFIELDS, $curl_post_data); 
$curl_response = curl_exec($curl); 
if ($curl_response === false) { 
    $info = curl_getinfo($curl); 
    curl_close($curl); 
    die('error occured during curl exec. Additional info: ' . var_export($info)); 
} 
curl_close($curl); 
$decoded = json_decode($curl_response); 
if (isset($decoded->response->status) && $decoded->response->status == 'ERROR') { 
    die('error occured: ' . $decoded->response->errormessage); 
} 
echo 'response ok!'; 
var_export($decoded->response); 

即使改变它像如下因素将无法正常工作:

$service_url = 'http://example.com/param/1'; 
$curl = curl_init($service_url); 

curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($curl, CURLOPT_POST, true); 
$curl_response = curl_exec($curl); 
if ($curl_response === false) { 
    $info = curl_getinfo($curl); 
    curl_close($curl); 
    die('error occured during curl exec. Additional info: ' . var_export($info)); 
} 
curl_close($curl); 
$decoded = json_decode($curl_response); 
if (isset($decoded->response->status) && $decoded->response->status == 'ERROR') { 
    die('error occured: ' . $decoded->response->errormessage); 
} 
echo 'response ok!'; 
var_export($decoded->response); 

这不是工作:但我想它仍然是一个GET

$service_url = 'http://example.com/param/1'; 
$curl = curl_init($service_url); 
$curl_response = curl_exec($curl); 
if ($curl_response === false) { 
    $info = curl_getinfo($curl); 
    curl_close($curl); 
    die('error occured during curl exec. Additional info: ' . var_export($info)); 
} 
curl_close($curl); 
$decoded = json_decode($curl_response); 
if (isset($decoded->response->status) && $decoded->response->status == 'ERROR') { 
    die('error occured: ' . $decoded->response->errormessage); 
} 
echo 'response ok!'; 
var_export($decoded->response); 

回答

0
$service_url = 'http://example.com/param/1';  
$ch = curl_init($service_url); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($ch, CURLOPT_POSTFIELDS, "param1=value1&param2=value2&.."); 
$response = curl_exec($ch); 
curl_close($ch); 
+0

不,不是。 param = 1是要传递的参数...您列出的后置字段不是必需的(param1,param2 ....) – koalaok