2017-03-27 71 views
0

我有一个问题。我想创建历史时间表,在此时间轴上,用户可以添加“元素”(例如每年的元素)。PHP中的循环表单,用1个按钮提交所有表单

在表格1中,用户的时间轴这得到发送到数据库(这部作品)上创建时间表,并表示元素的含量。 在表单2中,用户可以填充元素。 (这不工作)。

在形式1(如果有人想5种元素)发布后,数据库创建5个记录(每个元素之一)。

现在我想的是,这些填充5个元素(标题,说明等)5种不同的形式,但与1提交按钮。

现在,如果我尝试这个(见下面的代码),只有第五形式被张贴... 我如何得到这个工作?

由于提前,

<?php 

error_reporting(E_ALL); 
ini_set('display_errors', 1); 

require_once('classes/database.class.php'); 

$DB = Database::getInstance(); 

$titel = ''; 
$beschrijving = ''; 
$afbeeldingURL = ''; 
$jaar = ''; 
$element_id = ''; 

$velden = ''; 

$sql3 = "SELECT `id` , `aantal_elementen` FROM `tijdlijn` ORDER BY id DESC LIMIT 0, 1"; 
$last_id = $DB->_query($sql3); 

if ($last_id->num_rows > 0) { 
    while($row = $last_id->fetch_assoc()) { 
     $last_id2 = $row["id"]; 
     $aantal_elementen3 = $row["aantal_elementen"]; 
    } 
} 

$sql4 = "SELECT * FROM `elementen` WHERE `tijdlijn_id` = ".$last_id2.""; 

$sql5 = "SELECT `id` FROM `elementen` WHERE `tijdlijn_id` = ".$last_id2." ORDER BY id ASC LIMIT 0,1"; 

$sql6 = "SELECT `id` FROM `elementen` WHERE `tijdlijn_id` = ".$last_id2." ORDER BY id DESC LIMIT 0,1"; 

$sql7 = "SELECT `id` FROM `elementen` WHERE `tijdlijn_id` = ".$last_id2." ORDER BY id ASC"; 

$last_id3 = $DB->_query($sql4); 

$min_id = $DB->_query($sql5); 
$min_id = mysqli_fetch_assoc($min_id); 
$min_id = $min_id['id']; 

$max_id = $DB->_query($sql6); 
$max_id = mysqli_fetch_assoc($max_id); 
$max_id = $max_id['id']; 

$dingid[] = $DB->_query($sql7); 

echo $min_id."</br>"; 
echo $max_id."</br>"; 
$current_id = $min_id; 

if (isset($_POST) && !empty($_POST)) { 

    $boolError = false; 

    foreach ($_POST as $k => $v) { 
     $_POST[$k] = trim($v); 
    } 

    if (!isset($_POST['titel']) || trim($_POST['titel']) == '') { 
     $titel = 'error'; 
     $boolError = true; 
    } 

    if (!isset($_POST['beschrijving']) || trim($_POST['beschrijving']) == '') { 
     $beschrijving = 'error'; 
     $boolError = true; 
    } 

    if (!isset($_POST['afbeeldingURL']) || trim($_POST['afbeeldingURL']) == '') { 
    } 

    if (!isset($_POST['jaar']) || trim($_POST['jaar']) == '') { 
     $jaar_start = 'error'; 
     $boolError = true; 
    } 

    if (
     !isset($_POST['element_id']) 
     || trim($_POST['element_id']) == '' 
     || !preg_match('/^\d+$/', $_POST['element_id']) 
    ) { 
     $element_id = 'error'; 
     $boolError = true; 
    } 


    if ($boolError === false) { 
     $sql = "UPDATE `elementen` 
       SET 
       `titel` = '" . $_POST['titel'] . "', 
       `beschrijving` = '" . $_POST['beschrijving'] . "', 
       `afbeelding_url` = '" . $_POST['afbeeldingURL'] . "', 
       `jaar` = '" . $_POST['jaar'] . "' 
       WHERE `id` = ".$_POST['element_id']."; 
     "; 


     if ($DB->_query($sql)) { 
     //$current_id++; 
     //exit; 


     } else { 
      header('Location: ?oops2'); 
      exit; 

     } 

    } else { 
     $velden = "Ff alles invullen he"; 
    } 
?> <p>Vul het formulier hier onder in voor de elementen en maak een tijdlijn!</p><?php 
} 

    if ($last_id3->num_rows > 0) { 
     while($row2 = $last_id3->fetch_assoc()) { 
      $last_id4 = $row2["id"]; 
?> 


     <form class="form-nieuws" method="post"> 

      </br></br> 
      <?php echo $last_id2; ?> 
      <?php echo $current_id; ?> 
      <input id="titel2" class="<?= $titel ?> form-control" type="text" placeholder="Titel tijdlijn" name="titel" value="<?= isset($_POST['titel']) ? $_POST['titel'] : '' ?>"> 
      <br> 
      <textarea id="beschrijving2" class="<?= $beschrijving ?> form-control" rows="3" placeholder="Beschrijving over tijdlijn" name="beschrijving" value="<?= isset($_POST['beschrijving']) ? $_POST['beschrijving'] : '' ?>"></textarea> 
      <br> 
      <input id="afbeeldingURL2" class="<?= $afbeeldingURL ?> form-control" type="text" placeholder="URL voor afbeelding" name="afbeeldingURL" value="<?= isset($_POST['afbeeldingURL']) ? $_POST['afbeeldingURL'] : '' ?>"> 
      <br>    
      <input id="jaar" class="<?= $jaar ?> form-control" type="text" placeholder="Start jaar tijdlijn" name="jaar" value="<?= isset($_POST['jaar']) ? $_POST['jaar'] : '' ?>"> 
      <input id="element_id" class="<?= $element_id ?> form-control" type="text" placeholder="<?php echo $last_id4 ?>" name="element_id" value="<?= isset($_POST['element_id']) ? $_POST['element_id'] : '' ?>"> 
      <div class="foutlabel"> 
       <em class="<?= ($velden) ? 'error' : '' ?>"><?= ($velden) ? $velden : '' ?> 
       </em> 
      </div> 
      </br>  


        <?php $current_id++;} 

        } ?> <div class="gabutton"> 
       <input type="submit" value="Creeer tijdlijn"> 
      </div> 


     </form> 

回答

2

的最佳方式是仅具有一个为每个元件输入形式。您可以根据元素生成每个表单输入。

用这种方式,你只需要一个按钮,一个电话将数据发送到服务器。

在服务器端,您只需要分析和检查数据,并要小心你发送元素的数量。

+0

这样做的一个有用的技巧是,如果输入名称中有方括号,PHP将在'$ _POST'中创建数组,例如, ''input type =“text”name =“foo []”/>','',或'' – IMSoP