查找字符

Question

我有一个看起来像这样从XLSX文件中去掉数据：

[6, 2]=>"Comment", [6, 3]=>"Complaint", [6, 4]=>"Enquiry" 

我想搜索的阵列和前括号返回第二个数字的值。即，搜索Complaint应该返回3。任何帮助表示赞赏。

NB - 根据对数组的注释更新。删除了OP中的字符串转换。

require 'roo' 

today_file=(File.dirname(__FILE__) + '/output/today-report.xlsx') 

def by_value(data, value) 
    found = data.find do |k, v| 
    v == value 
    end 

    found and found[0][1] 
end 

data = Roo::Excelx.new (today_file) 

output = by_value(data, "Complaint").inspect 

puts output 

当运行这个返回“零”

从这个阵列的输出是这种形式：

{[1, 1]=>"YESTERDAY - 02/10/14", [1, 4]=>"Another comment below the fold - scroll down", [2, 1]=>"Yesterday we received 11 regarding the service.", [4, 1]=>"TYPE", [6, 1]=>"", [6, 2]=>"Comment", [6, 3]=>"Complaint", [6, 4]=>"Enquiry", [6, 5]=>"Total (Type)", [7, 1]=>"Editorial and other queries", [7, 2]=>1.0, [7, 3]=>7.0,...} 

Answer 1

这是一个奇怪的要求。这是如何做到这一点。

word = "Complaint" 
data_string[/, (\d+)\]=>"#{Regexp.escape(word)}"/, 1] # => "3" 

Answer 2

如果你是新来的Ruby，你会想花时间熟悉Enumerable库。它有很多操作和提取数据的工具。

在这种情况下，find这项工作：

def by_value(data, value) 
    # Find the key/value pair where the value matches 
    found = data.find do |k, v| 
    v == value 
    end 

    # If one of these was found, pull the second number from the key 
    found and found[0][1] 
end 

data = {[6, 2]=>"Comment", [6, 3]=>"Complaint", [6, 4]=>"Enquiry"} 

puts by_value(data, "Complaint").inspect 
# => 3 

值得一提的是，这是一个相对缓慢的操作，因为你正在做一个线性搜索。如果这样做了足够频繁你要反转它使搜索更快：

def by_value(data, value) 
    found = data[value] 

    found and found[1] 
end 

# Using Hash#invert switches the keys and values so you can now look-up by value 
data = {[6, 2]=>"Comment", [6, 3]=>"Complaint", [6, 4]=>"Enquiry"}.invert 

puts by_value(data, "Complaint").inspect 
# => 3