阵列中的Hive列数据

Question

我有一个包含小时级数据的表。我想查找小时数和数组中所有小时的值。 输入表

+-----+-----+-----+ 
| hour| col1| col2| 
+-----+-----+-----+ 
| 00 | 0.0 | a | 
| 04 | 0.1 | b | 
| 08 | 0.2 | c | 
| 12 | 0.0 | d | 
+-----+-----+-----+ 

如以下溶液建议我使用函数来获取上述列值的数组

SELECT COUNT（小时），map_values（str_to_map（CONCAT_WS（ ''，collect_set（ concat_ws（'：'，reflect（'java.util.UUID'，'randomUUID'），cast（col1 as string））））））as col1_arr， map_values（str_to_map（concat_ws（'，'，collect_set（concat_ws '：'，reflect（'java.util.UUID'，'randomUUID'），cast（col12 as string））））））as col2_arr from table;

我得到的输出，col2_arr中的值与col1_arr的顺序不同。请建议如何以相同的顺序获取不同列的数组/列表中的值。

+----------+-----------------+----------+ 
| count(hr)| col1_arr  | col2_arr | 
+----------+-----------------+----------+ 
| 4  | 0.0,0.1,0.2,0.0 | b,a,c,d | 
+----------+----------------+-----------+ 

需要的输出：

+----------+-----------------+----------+ 
| count(hr)| col1_arr  | col2_arr | 
+----------+-----------------+----------+ 
| 4  | 0.0,0.1,0.2,0.0 | a,b,c,d | 
+----------+----------------+-----------+ 

感谢

Answer 1

with t as 
     ( 
      select inline 
        (
         array 
         (
          struct('00',0.0) 
          ,struct('04',0.1) 
          ,struct('08',0.2) 
          ,struct('12',0.0) 
         ) 
        ) as (hour,col1) 
     ) 

select count(*),collect_list(col1),max(col1) 
from t 
; 

---

+-----+-------------------+-----+ 
| _c0 |  _c1  | _c2 | 
+-----+-------------------+-----+ 
| 4 | [0.0,0.1,0.2,0.0] | 0.2 | 
+-----+-------------------+-----+ 

如果要保证阵列，使用中的元素的顺序 -

sort_array(collect_list(col1)) 

如果你想消除数组中的元素的副本，使用 -

collect_set(col1) 

---

保持重复的值，而不collect_list

with t as 
     ( 
      select inline 
        (
         array 
         (
          struct('00',0.0) 
          ,struct('04',0.0) 
          ,struct('08',0.1) 
          ,struct('12',0.1) 
         ) 
        ) as (hour,col1) 
     ) 

select map_values(str_to_map(concat_ws(',',collect_set(concat_ws(':',reflect('java.util.UUID','randomUUID'),cast(col1 as string)))))) 
from t 
; 

---

["0.0","0.0","0.1","0.1"]