2012-03-08 89 views
3

我具有编组使用JAXB元帅使用JAXB

一个对象的迭代问题对象的一个​​迭代

用户类:

@XmlRootElement(name="User") 
public class User{ 
    private Long id; 
    private String name,mailid; 
    private boolean isActive; 
    public Long getId() { 

     return id; 
    } 
    public void setId(Long id) { 
     this.id = id; 
    } 
    public String getName() { 
     return name; 
    } 
    public void setName(String name) { 
     this.name = name; 
    } 
    public String getMailid() { 
     return mailid; 
    } 
    public void setMailid(String mailid) { 
     this.mailid = mailid; 
    } 
    public boolean isActive() { 
     return isActive; 
    } 
    public void setActive(boolean isActive) { 
     this.isActive = isActive; 
    } 

} 

该函数返回的用户的Iterator:

public static Iterator<User> mapDoToUserObject(DataObject dao){ 

    final Iterator<Row> userRow = getRow(dao,USER.TABLE); 


    return new Iterator<User>() { 
     @Override 
     public boolean hasNext() { 
      return userRow.hasNext(); 
     } 

     @Override 
     public User next() { 
      Row user = userRow.next(); 
      User user = new User(); 
      user.setId((Long)user.get(USER.USER_ID)); 
      user.setName((String) user.get(USER.FIRST_NAME)); 
      user.setMailid((String)user.get(USER.EMAIL_ID)); 
      return user; 
     } 

     @Override 
     public void remove() { 
      throw new UnsupportedOperationException("Remove not supported"); 

     } 
    }; 
} 

如何编组用户使用JAXB的迭代器?

回答

4

您将需要将迭代器抽取到集合中,然后封送(这是最简单的解决方案),或者使用JAXB的增量编组功能,这意味着您自己迭代迭代器并编组单个对象。有关如何操作的说明,请参阅Can JAXB Incrementally Marshall An Object?