2017-06-16 121 views
0

我在获取当前用户在django rest框架中上传图像时遇到了很多麻烦。在django rest框架中获取当前用户

Django rest框架是用于网页的纯django内的应用程序。

我使用django rest框架,以便用户可以上传我们的服务器上的文件......除了我们需要知道谁是上传它的用户,一切都很好。我真的尝试过很多这个网站和谷歌提供的解决方案,但只是无法实现。这是来自应用程序的代码。我们该做什么?

viewset.py

from rest_framework import viewsets, filters 
from api.serializers import UploadedImageSerializer # import our serializer 
from api.models import UploadedImage # import our model 

class UploadedImagesViewSet(viewsets.ModelViewSet): 
    queryset = UploadedImage.objects.order_by('-id')[:1] 
    serializer_class = UploadedImageSerializer 

serializer.py

from rest_framework import serializers 
from api.models import UploadedImage # Import our UploadedImage model 


class UploadedImageSerializer(serializers.ModelSerializer): 
    # Create a custom method field 
# current_user = serializers.SerializerMethodField('_user') 

class Meta: 
    model = UploadedImage 
    fields = ('id', 'image','name','Tip','curent_user') # only serialize the primary key and the image field 

models.py

from django.db import models 
import uuid,os 
import sqlite3 
import Function1 
import Function2 
from django.contrib.auth.models import User 

def scramble_uploaded_filename(instance, filename): 
    extension = filename.split(".")[-1] 

    return "{}.{}".format(uuid.uuid4(), extension) 

def filename(instance, filename): 
    return filename 


# Our main model: Uploaded Image 
class UploadedImage(models.Model): 
    image = models.ImageField("Uploaded image",upload_to=scramble_uploaded_filename) 
    Tip = models.IntegerField("Captcha type") 
    curent_user = models.CharField("Curent user",editable=False,max_length=100,default='') 

    def filen(self) : 
     path = self.image.path 
     tip = self.Tip 
     writez = Function1.File_input(path,tip) 
     text = Function2.File_input (writez,0.83,tip) 
     return text 
    name = filen 

views.py

from rest_framework import viewsets 
from api.serializers import UploadedImageSerializer 
from api.models import UploadedImage 


class UploadViewSet(viewsets.ModelViewSet): 
    """ 
    API endpoint 
    """ 
    queryset = UploadedImage.objects.all() 
    serializer_class = UploadedImageSerializer 

回答

1

这对我有用。你在上传类(在我的例子中为Post)中创建一个ForeignKey并将其链接到用户(不要忘记进行迁移和迁移)。在您的视图中,当您呈现表单时,请使用instance = form.save(commit = False) - >instance.uploaded_by = request.user - >instance.save(),以便抓取当前用户及其保存在发布(上传)模型中的用户。

views.py:

def upload(request): 
    form = PostForm(request.POST or None, request.FILES or None) 
    if form.is_valid(): 
     instance = form.save(commit = False) 
     instance.uploaded_by = request.user 
     instance.save() 
     form.save_m2m() 

models.py:

class Post(models.Model): 
     uploaded_by = models.ForeignKey('auth.User',default=1,related_name='uploads') 
     ... 

要看到,你会在你的应用程序admin.py安装现场 “uploaded_by” 管理员用户。我假设你知道如何不谷歌将帮助你;) 希望有所帮助。

+0

我的代码有了一些进步,它帮助我理解了它的工作原理。我找到后我会回复你。 Ty为您提供帮助。 –

+0

我做了tnx人! –

+0

所以它显示在管理员?你写的其他评论是什么?有麻烦的ID?听起来像你需要定义def'__str __(self): \t \t返回模型中的self.user.userprofile.name'。我的代码是否为您提供解决方案,或者您找到了自己的解决方案?无论如何,我很高兴你做到了。 – hansTheFranz

1

在我的项目中,我使用HiddenField填充当前用户。例如你的情况:

class UploadedImageSerializer(serializers.ModelSerializer): 
    current_user = serializers.HiddenField(default=serializers.CurrentUserDefault()) 

    class Meta: 
     model = UploadedImage 
     fields = ('id', 'image','name','Tip','current_user') 
+0

你的代码和@hansTheFranz的组合对我来说是一种胜利的解决方案。 TNX –