客户端响应应用程序.Json

我正在尝试为某些Rest应用程序创建客户端。我在Chrome中使用高级REST客户端测试了其他应用程序。客户端响应应用程序.Json

我收到：

{ 
    "authorization": false, 
    "provider": "Provider" 
}

即好。但我想在我的客户获得此：

λ java -jar Client_consumer-1.0-SNAPSHOT.jar 
or[email protected]6591f517

类是：

@XmlRootElement 
public class Auth_response implements Serializable { 
private String Provider; 
private boolean authorization; 

public Auth_response() { 
    super(); 
} 

public Auth_response(String Provider, boolean authorization) { 
    super(); 
    this.Provider = Provider; 
    this.authorization = authorization; 
} 

public String getProvider() { 
    return Provider; 
} 

public boolean isAuthorization() { 
    return authorization; 
} 

public void setProvider(String Provider) { 
    this.Provider = Provider; 
} 

public void setAuthorization(boolean authorization) { 
    this.authorization = authorization; 
} 

@Override 
public String toString() { 
    return "Auth_response{" + "Provider=" + Provider + ", authorization=" + authorization + '}'; 
}

}

我

public class MainApp extends Application { 
    public static final String BASE_URI = "http://localhost:8000/test"; 
    public static final String PATH_NAME= "/sytem/Consumer/r/Provider"; 

@Override 
public void start(Stage stage) throws Exception { 
} 

public static void main(String[] args) { 

    Client client = ClientBuilder.newClient(); 
    WebTarget target = client.target(BASE_URI).path(PATH_NAME); 
    Response response = target.request(MediaType.APPLICATION_JSON).get(); 
    System.out.println(response); 
    client.close(); 

} 

}

我只在终端接收此想知道如何正确打印响应，以及如何再次转换为java对象。我尝试了一些例子，但没有任何作品，我认为我需要一些指导。

编辑：我想这样来的对象：

Auth_response r= 
client.target("http://localhost:8000/test/system/Consumer/r/Provider") 
.request(MediaType.APPLICATION_JSON_TYPE). 
get(Auth_response.class); 
    System.out.println("funciona:"); 
    System.out.println(r.getProvider()); 
    System.out.println(r.isAuthorization());

但我得到一个错误：

Caused by: javax.ws.rs.ProcessingException: RESTEASY003145: Unable to find a MessageBodyReader of content-type application/json and type class ah.client_consumer.Auth_response 
    at org.jboss.resteasy.core.interception.ClientReaderInterceptorContext.throwReaderNotFound(ClientReaderInterceptorContext.java:42) 
    at org.jboss.resteasy.core.interception.AbstractReaderInterceptorContext.getReader(AbstractReaderInterceptorContext.java:75) 
    at org.jboss.resteasy.core.interception.AbstractReaderInterceptorContext.proceed(AbstractReaderInterceptorContext.java:52) 
    at org.jboss.resteasy.plugins.interceptors.encoding.GZIPDecodingInterceptor.aroundReadFrom(GZIPDecodingInterceptor.java:59) 
    at org.jboss.resteasy.core.interception.AbstractReaderInterceptorContext.proceed(AbstractReaderInterceptorContext.java:55) 
    at org.jboss.resteasy.client.jaxrs.internal.ClientResponse.readFrom(ClientResponse.java:251) 
    at org.jboss.resteasy.client.jaxrs.internal.ClientResponse.readEntity(ClientResponse.java:181) 
    at org.jboss.resteasy.specimpl.BuiltResponse.readEntity(BuiltResponse.java:213) 
    at org.jboss.resteasy.client.jaxrs.internal.ClientInvocation.extractResult(ClientInvocation.java:105) 
    ... 14 more

异常运行的应用程序ah.client_consumer.MainApp

来源

2017-09-26 cristina paniagua

误差'致HTTP 404未找到'表示您尝试访问的Web服务无法访问。你可以请张贴那部分吗？ –

当我使用高级客户端休息时，Web服务工作。 –

我在路径中发生了错误，我编辑了当前错误的错误。 –

尝试改变下线：

Response response = target.request(MediaType.APPLICATION_JSON).get(); 
System.out.println(response);

要

Response response = target.request(MediaType.APPLICATION_JSON).get(String.class); 
System.out.println(response.toString());

因为你还没有指定您接受什么类型的反应，你得到对象作为响应。

来源

2017-09-26 14:21:34

我试过，我获得：or[email protected]6591f517 –

SOLUTION：

添加到代码：

ResteasyProviderFactory instance=ResteasyProviderFactory.getInstance(); 
RegisterBuiltin.register(instance); 
instance.registerProvider(ResteasyJacksonProvider.class);

将该溶液在发现：javax.ws.rs.NotFoundException：Unable to find a MessageBodyReader of content-type application/json and type class java.lang.String

来源

2017-09-26 15:06:11

客户端响应应用程序.Json

回答

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