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我有一个窗体对话框QDialog使用QDataWidgetMapper更新QTableView行的数据。该项目包含QString数据,但我只想显示QCheckBox并使用QCheckbox上的动态属性在后台设置状态更改的值。如何使用QDataWidgetMapper恢复对象的动态属性?
所有事件(toFirst,toLast,toNext,toPrevious,submit)按预期工作,但恢复不撤销显示的状态。
有没有可以使用的信号?或者我应该尝试覆盖恢复槽?任何建议?
(代码去除,以保持它的简单等小部件)
EditDialog::EditDialog(QStandardItemModel &model, QModelIndex ¤t, QWidget *parent)
: QDialog(parent)
{
cbHomeCLI = new QCheckBox();
// other widgets ......
dataMapper->setModel(&model);
dataMapper->setSubmitPolicy(QDataWidgetMapper::ManualSubmit);
dataMapper->addMapping(cbHomeCLI,3,"useCLI");
// button connects for toFirst, toXXXX, ..., here ....
connect(bttnDiscard,&QPushButton::clicked,dataMapper,&QDataWidgetMapper::revert);
connect(cbHomeCLI,&QCheckBox::stateChanged,this,&EditDialog::changeProperty);
connect(dataMapper,&QDataWidgetMapper::currentIndexChanged,this,&EditDialog::initState);
QGridLayout *layout(new QGridLayout());
layout->addWidget(cbHomeCLI,2,2);
setLayout(layout);
setWindowTitle("....");
dataMapper->setCurrentModelIndex(current);
}
void EditDialog::initState(int row)
{
QStandardItemModel *mdl = qobject_cast<QStandardItemModel *>(dataMapper->model());
if (mdl->item(row,3)->text() == "*31#")
cbHomeCLI->setChecked(true);
else
cbHomeCLI->setChecked(false);
}
void EditDialog::changeProperty(int state)
{
QCheckBox *from = qobject_cast<QCheckBox *>(sender());
if (state)
from->setProperty("useCLI",QString("*31#"));
else
from->setProperty("useCLI",QString(""));
}