在阅读了有关类似主题的其他问题之后,我仍然不明白这段代码有什么问题。Django Jquery不需要AJAX请求
我正在测试使用Jquery Form插件的代码。我在视图中向模板添加了一个呼叫,以便第一次显示它,以便用户可以选择文件并上传。但它从不发送AJAX请求,因此视图中的代码段不会被执行。尽管这里没有显示,但jQuery库和jQueryForm插件确实被调用。
Template:
<form id="uploadForm" method="post" enctype="multipart/form-data">
{% csrf_token %}
<input id="fileInput" class="input-file" name="upload" type="file">
{{ form.docfile }}
<span class="upload-message"></span>
<input type="submit" value="Upload" />
</form>
<script>
var message = '';
var options = {
type: "POST",
url: '/upload/file/',
error: function(response) {
message = '<span class="error">We\'re sorry, but something went wrong. Retry.</span>';
$('.upload-message').html(message);
$('fileInput').val('');
},
success: function(response) {
message = '<span class="' + response.status + '">' + response.result + '</span> ';
message = (response.status == 'success') ? message + response.fileLink : message;
$('.upload-message').html(message);
$('fileInput').val('');
}
};
$('#uploadForm').ajaxSubmit(options);
</script>
查看:
def upload(request):
response_data = {}
if request.method == 'POST':
if request.is_ajax:
form = UploaderForm(request.POST, request.FILES)
if form.is_valid():
upload = Upload(
upload=request.FILES['upload']
)
upload.name = request.FILES['upload'].name
upload.save()
response_data['status'] = "success"
response_data['result'] = "Your file has been uploaded:"
response_data['fileLink'] = "/%s" % upload.upload
return HttpResponse(json.dumps(response_data), content_type="application/json")
response_data['status'] = "error"
response_data['result'] = "We're sorry, but kk something went wrong. Please be sure that your file respects the upload conditions."
return HttpResponse(json.dumps(response_data), content_type='application/json')
else:
form = UploaderForm()
return render(request, 'upload.html', {'form': form})
它在第一次做正确调用模板,它显示的按钮,它会再次执行脚本,但形式是无效的,所以RESPONSE_DATA是错误。
我错过了什么?
谢谢,里卡多
所以点击“提交”后,ajax根本不运行? – mariodev
如果脚本中没有数据发送,它应该如何工作? – catherine
嗨里卡多,你是否设法解决这个问题?我面临同样的问题。需要帮助! – g4ur4v