任何人都可以告诉我这里发生了什么。我不知道为什么这个代码不工作,并抛出以下错误:SQL语法错误 - PHP/MySQL
You have an error in your SQL syntax, check the manual that corresponds to your MySQL server version for the right syntax to use near 'AND role != 7 AND role != 4' at line 3
$sql = 'SELECT * FROM tblusers
INNER JOIN permissions on tblusers.usrID = permissions.user_id
WHERE permissions.team_id='.$team_id.' AND role != 7 AND role != 4';
require("connection.php");
$result = mysql_db_query($DBname,$sql,$link) or die(mysql_error());
while($row = mysql_fetch_assoc($result))
{
$message->addTo($row['usrEmail'], $row['usrFirst'] . ' ' . $row['usrLast']);
}
我知道变量$ TEAM_ID工作正常,因为如果我“回声”,它的工作原理精细。我在这里做错了什么想法?谢谢!
尝试呼应$ SQL变量,通常是调试这些类型的错误的一个很好的办法。 – Tjofras 2009-11-07 00:46:01