form.is_valid
在views.py中总是返回false。我用Django表单来创建一个表单和html来实现它。form.is_valid始终返回false
我会将这张照片上传到imgur,使用imgurpython后来,但首先这应该工作。
views.py
def upload_view(request):
usr = check_validation(request)
if usr:
if request.method == "GET":
form = PostForm()
return render(request, 'upload.html', {'form': form})
elif request.method == "POST":
form = PostForm(request.POST, request.FILES)
if form.is_valid():
pic = form.cleaned_data.get('image')
title = form.cleaned_data.get('caption')
post = PostForm()
post.user = usr
post.caption = title
post.image = pic
post.save()
return redirect('feed/')
else:
return render(request, 'upload.html', {'error_msg' : "Invalid Inputs"})
else:
return redirect('/login/')
models.py
class Post(models.Model):
user = models.ForeignKey(User)
image = models.FileField(upload_to='user_images')
caption = models.CharField(max_length=240)
image_url = models.CharField(max_length=255)
created_on = models.DateTimeField(auto_now_add=True)
forms.py
class PostForm(forms.ModelForm):
class Meta:
model = Post
fields = ['user', 'image', 'caption']
模板 - upload.html
<form method="post" enctype="multipart/form-data" class="loginbox" style="margin-top:200px;">
{% csrf_token %}
<p class="text-16">Upload to aperture.</p>
{{ form }}
<p class="text-16">{{ error_msg }}</p>
<input class="login-btn" type="submit" value="Upload"/>
</form>
请阅读[在什么情况下,我可以添加“紧急”或其他类似的短语到我的问题,以获得更快的答案?](/ meta.stackoverflow.com/q/326569) - 总结是,这不是解决志愿者问题的理想方式,而且可能对获得答案起反作用。请不要将这添加到您的问题。 – halfer