我可以在jQuery中使用Ajax Control Toolkit客户端吗？

Question

这是根据我的可能与Ajax库。但是，这似乎已经过时了？

Answer 1

根据我的说法，没有理由不能使用jQuery的microsoft ajax客户端javascript库。

我认为你可以像你一样正常访问它。试试这个，看看它是否有效。让你参考上面的microsoft ajax库和jQuery库。

$(document).ready(function() { 
    Type.registerNamespace("Demo"); 

Demo.Person = function(firstName, lastName, emailAddress) { 
    this._firstName = firstName; 
    this._lastName = lastName; 
    this._emailAddress = emailAddress; 
} 

Demo.Person.prototype = { 
    getFirstName: function() { 
     return this._firstName; 
    }, 

    getLastName: function() { 
     return this._lastName; 
    }, 

    getEmailAddress: function() { 
     return this._emailAddress; 
    }, 
    setEmailAddress: function(emailAddress) { 
     this._emailAddress = emailAddress; 
    }, 

    getName: function() { 
     return this._firstName + ' ' + this._lastName; 
    }, 

    dispose: function() { 
     alert('bye ' + this.getName()); 
    }, 

    sendMail: function() { 
     var emailAddress = this.getEmailAddress(); 

     if (emailAddress.indexOf('@') < 0) { 
      emailAddress = emailAddress + '@example.com'; 
     } 
     alert('Sending mail to ' + emailAddress + ' ...'); 
    }, 

    toString: function() { 
     return this.getName() + ' (' + this.getEmailAddress() + ')'; 
    } 
} 

Demo.Person.registerClass('Demo.Person', null, Sys.IDisposable); 
Demo.Employee = function(firstName, lastName, emailAddress, team, title) { 
    Demo.Employee.initializeBase(this, [firstName, lastName, emailAddress]); 

    this._team = team; 
    this._title = title; 
} 

Demo.Employee.prototype = { 

    getTeam: function() { 
     return this._team; 
    }, 
    setTeam: function(team) { 
     this._team = team; 
    }, 

    getTitle: function() { 
     return this._title; 
    }, 
    setTitle: function(title) { 
     this._title = title; 
    }, 
    toString: function() { 
     return Demo.Employee.callBaseMethod(this, 'toString') + '\r\n' + this.getTitle() + '\r\n' + this.getTeam(); 
    } 
} 
Demo.Employee.registerClass('Demo.Employee', Demo.Person); 
});