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我想在OnItemClick中的两件事之间有一些延迟,但实际上并没有发生。如果我运行它并单击,则只要设置了睡眠,所有内容都会停止,然后它会同时更改图片。我想更改第一张图片。然后睡眠,然后改变其他。Sleep Inside onItemClick
gv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
// clicks=0;
int row_no = position/3;
int col_no = position % 3;
if(clicks==0)
{
((ImageView) gv.getChildAt(position)).setImageResource(R.drawable.kor);
matrix[row_no][col_no]=1;
// clicks++;
}
if(gepLephet())
{
try {
Thread.sleep(400);
} catch (InterruptedException e) {
e.printStackTrace();
}
finally{
int posAi=gep();
((ImageView) gv.getChildAt(posAi)).setImageResource(R.drawable.iksz);
matrix[posAi/3][posAi%3]=2;
}
// Toast.makeText(getApplicationContext(),"Random: "+posAi, Toast.LENGTH_SHORT).show();
}
/* else if(clicks==1)
{
((ImageView) gv.getChildAt(position)).setImageResource(R.drawable.iksz);
matrix[row_no][col_no]=2;
clicks--;
}*/
// Toast.makeText(getApplicationContext(), "position: " + position +"Random: "+posAi, Toast.LENGTH_SHORT).show();
// if(matrix[0][0]==matrix[0][1]&&matrix[0][1]==matrix[0][2]){text.setText("WIN");}
if(isWinO())
{
text.setText("O WIN");
}
if(isWinX())
{
text.setText("X WIN");
}
}
;
});
你需要另一个线程 - 看看这个答案更新UI线程和延缓http://stackoverflow.com/a/14088164/1256219 – brandall 2014-10-04 18:12:34
没有用户'Timer',使用'postDelayed' – Budius 2014-10-04 18:31:07