Sequelize：根据关联的属于多个记录查找记录 - 但仍然返回所有关联的记录？

Question

我有两个belongsToMany型号：

const apptsModel = db.define('Appts', { 
    id: {type: Sequelize.INTEGER, primaryKey: true, autoIncrement: true}, 
    [.....] 
}); 

const UserDataModel = db.define('UserData', { 
    id: {type: Sequelize.STRING, primaryKey: true}, 
    gender: {type: Sequelize.STRING}, 
    name_title: {type: Sequelize.STRING}, 
    name_first: {type: Sequelize.STRING}, 
    name_last: {type: Sequelize.STRING}, 
    [.....] 
}); 

apptsModel.belongsToMany(UserDataModel, {through: 'ApptsToUsers'}); 
UserDataModel.belongsToMany(apptsModel, {through: 'ApptsToUsers'}); 

我想做一个搜索：

1）查找所有预约，相关联的用户中至少一个有一个特定的用户ID。

2）返回该约会的所有关联用户。

我有工作sequelize代码，不会（1）：

var ret = connectors.Appts.findAll({ 
    include: [connectors.UserData], 
    where: {'$UserData.id$': args.originatingUserID} 
}).then((res) => res.map((item) => item.dataValues)); 

...但它仅用于返回一个指定的用户关联的用户数据。如何为每个约会返回所有关联用户的数据？

Answer 1

目前似乎还没有很多关于如何做到这一点的文档。这工作，所以我会在这里发布这里供参考。

getAllApptsForCurrentUser(_, args) { 
     return Promise.resolve() 
      .then(() => { 
       //find all appointments and find those for which at least one 
       //participating user is the one specified in originatingUserID 
       var appts = connectors.Appts.findAll({ 
        include: [{ 
         model: connectors.UserData, 
         where: {id: args.originatingUserID} 
        }], 
       }).then((res) => res.map((item) => item.dataValues)); 
       return appts; 
      }) 
      .then(appts => { 
       //iterate returned appointments and perform a subquery on each, 
       //finding the other participating users 
       var arrayOfPromises = []; 
       appts.forEach(function (appt) { 
        arrayOfPromises.push(
         connectors.Appts.findOne({where: {id: appt.id}, order: [['apptDateTime']], include: [ connectors.UserData ] }) 
        ); 
       }); 
       //Promise.all returns true when all promises passed to it have 
       //returned true, or when one of them returns false 
       return Promise.all(arrayOfPromises); 
      }) 
      .then(apptsWithJoinedData => { 
       //console.log(apptsWithJoinedData); 
       return apptsWithJoinedData; 
      }) 
      .catch((err)=> { 
       console.log(err); 
      }); 
    } 

如果有更好的方法来做到这一点，请让我知道。