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我正在关注this link以获取访问令牌,但有些漏洞在下面的代码中,特别是在网址和内容中。ios - 如何获取访问令牌?
-(void)connectionDidFinishLoading:(NSURLConnection *)connection
{
if(_data)
{
NSString* content = [[NSString alloc] initWithData:_data
encoding:NSUTF8StringEncoding];
[_data release];
_data = nil;
NSString *jsString = @"<script type='text/javascript'>\
window.external =\
{\
'Notify': function(s) { document.location = 'acs://settoken?token=' + s; },\
'notify': function(s) { document.location = 'acs://settoken?token=' + s; }\
}\
</script>";
//Here appending the above javascript with content
content = [jsString stringByAppendingString:content];
NSURL *url = [[NSURL alloc] initWithString:@"https://converse.accesscontrol"];
[webView loadHTMLString:content baseURL:url];
}
}
当登录到Gmail或Yahoo,下面的代码将被解雇,然后检查URL,但在这里(如果条件不满足)。如果你能不能够明白,我想要问。请参阅上面给出的链接。
- (BOOL)webView:(UIWebView *)webView
shouldStartLoadWithRequest:(NSURLRequest *)request
navigationType:(UIWebViewNavigationType)navigationType
{
_url = [[NSURL alloc] initWithString:@"https://converse.accesscontrol.windows"];
if(_url)
{
if([_url isEqual:[request URL]])
{
return YES;
}
[_url release];
}
_url = [[request URL] retain];
NSString* scheme = [_url scheme];
if([scheme isEqualToString:@"acs"])
{
// parse the JSON URL parameter into a dictionary
NSDictionary* pairs = [self parsePairs:[_url absoluteString]];
if(pairs)
{
WACloudAccessToken* accessToken;
accessToken = [[WACloudAccessToken alloc] initWithDictionary:pairs];
[WACloudAccessControlClient setToken:accessToken];
[self dismissModalViewControllerAnimated:YES];
}
return NO;
}
[NSURLConnection connectionWithRequest:request delegate:self];
return NO;
}
任何想法?提前致谢。
感谢您的回复,我们为什么需要这个设备我要去的路吗? – 2013-05-02 07:27:25
你得到并享受 – hitesh 2013-05-02 07:32:46
你的代码加载在Safari中的内容,它是如此复杂的获取令牌,我试图加载在UIWebview – 2013-05-02 07:35:40