MySql的排除查询

Question

我有一个表，看起来像这样

JOB_ID | Email  | Type  | Date  
_____________________________________ 
28319 | mike@aol.com | Service | 11-24-2016 
_____________________________________ 
28412 | mike@aol.com | Rotation | 11-24-2016 
_____________________________________ 
38123 | andy@aol.com | Service | 11-24-2016 
_____________________________________ 
28199 | roger@aol.com| Service | 11-24-2016 

什么是查询我会跑回到那些谁安排了服务，但没有在特定日期的旋转。

这是我的尝试：

SELECT j.Job_ID,j.Email,j.Type,j.Date 
from Jobs j 
join 
    Jobs j2 
    on j.Email = j2.Customer_Email 
where j2.JOB_ID NOT IN (select j.JOB_ID 
        from Jobs j 
        where j.Type = 'Rotation' 
       )  AND j.Date = '11-24-2016'; 

所以我的查询将返回安迪和罗杰。

Answer 1

这应该做的伎俩给你，没有必要加入这里：一边

SELECT * FROM Jobs WHERE Date = '11-24-2016' AND Type = 'Service' AND 
Email NOT IN (SELECT Email FROM Jobs WHERE Date = '11-24-2016' AND 
Type = 'Rotation');