捕捉|右侧的词（或）在正则表达式不是在左边

Question

我试图捕获这个正则表达式右侧没有捕获到左侧的单词。

在下面的代码，左侧捕获“17英寸”在此字符串：“这235/45R17的17寸轮胎”

(?<=([-.0-9]+(\s)(inches|inch)))|??????? 

然而，什么我把在右侧，这样的作为一个简单的+ w是干扰左侧

我如何告诉RegEx捕获任何单词，除非它是一个数字后面英寸 - 在这种情况下捕获17和英寸？

Answer 1

说明

((?:(?![0-9.-]+\s*inch(?:es)?).)+)|([0-9.-]+\s*inch(?:es)?) 

_{**要看到图像更好，只需右键点击新窗口}

例

现场演示的图像，然后选择视图

https://regex101.com/r/fY9jU5/2

示例文本

this 235/45R17 is a 17 inch tyre 

样品匹配

• 捕获组1将是不匹配的17 inch
• 捕获组2将值是inche的数量小号

MATCH 1 
1. [0-20] `this 235/45R17 is a ` 

MATCH 2 
2. [20-27] `17 inch` 

MATCH 3 
1. [27-32] ` tyre` 

说明

NODE      EXPLANATION 
---------------------------------------------------------------------- 
    (      group and capture to \1: 
---------------------------------------------------------------------- 
    (?:      group, but do not capture (1 or more 
          times (matching the most amount 
          possible)): 
---------------------------------------------------------------------- 
     (?!      look ahead to see if there is not: 
---------------------------------------------------------------------- 
     [0-9.-]+     any character of: '0' to '9', '.', 
           '-' (1 or more times (matching the 
           most amount possible)) 
---------------------------------------------------------------------- 
     \s*      whitespace (\n, \r, \t, \f, and " ") 
           (0 or more times (matching the most 
           amount possible)) 
---------------------------------------------------------------------- 
     inch      'inch' 
---------------------------------------------------------------------- 
     (?:      group, but do not capture (optional 
           (matching the most amount 
           possible)): 
---------------------------------------------------------------------- 
      es      'es' 
---------------------------------------------------------------------- 
     )?      end of grouping 
---------------------------------------------------------------------- 
    )      end of look-ahead 
---------------------------------------------------------------------- 
     .      any character except \n 
---------------------------------------------------------------------- 
    )+      end of grouping 
---------------------------------------------------------------------- 
)      end of \1 
---------------------------------------------------------------------- 
|      OR 
---------------------------------------------------------------------- 
    (      group and capture to \2: 
---------------------------------------------------------------------- 
    [0-9.-]+     any character of: '0' to '9', '.', '-' 
          (1 or more times (matching the most 
          amount possible)) 
---------------------------------------------------------------------- 
    \s*      whitespace (\n, \r, \t, \f, and " ") (0 
          or more times (matching the most amount 
          possible)) 
---------------------------------------------------------------------- 
    inch      'inch' 
---------------------------------------------------------------------- 
    (?:      group, but do not capture (optional 
          (matching the most amount possible)): 
---------------------------------------------------------------------- 
     es      'es' 
---------------------------------------------------------------------- 
    )?      end of grouping 
---------------------------------------------------------------------- 
)      end of \2 
---------------------------------------------------------------------- 

Answer 2

它更容易，更安全的没什么只是先更换所有不想要的东西。
只有匹配你正在寻找的东西。

例如在此JavaScript例如：

var str = "this 235/45R17 is a 17 inch tyre of more than 9 inches."; 
var result = str.replace(/\s[\d.\-]+\sinch(?:es)?/gi, "").match(/\-?\d+\.?\d*/gi); 

为了得到结果235,45,17

负先行是可能的，但最好使用词语边界\湾
为了避免像仍然匹配数字中不应该匹配的第一个数字的问题。

例如：

var result = str.match(/(?:\-?\d+\.?\d*)(?:[a-z]|\b)(?!\s+inch(?:es)?)/gi); 

为了让结果235,45R,17