laravel like query is not working？

这是我的代码：laravel like query is not working？

$lists = DB::table('connection_request as cr') 
        ->leftJoin('users as u', function($join) 
         { 
          $join->on('u.id', '=', 'cr.sender_id')->orOn('u.id','=', 'cr.receiver_id'); 
         }) 
        ->select('cr.id as connection_id','cr.sender_id as sen_id','cr.receiver_id as rec_id','cr.approve_status','u.id','u.user_type','u.user_type_id',DB::raw("IF(u.avatar = '', 'uploads/avatar/default.jpg', u.avatar) as avatar"),'u.name','u.email') 
        ->where(function($query) use ($user_id) 
         { 
         if(!empty($user_id)): 
          $query->Where('cr.receiver_id','=', $user_id); 
         endif; 
         if(!empty($user_id)): 
          $query->orWhere('cr.sender_id','=', $user_id); 
         endif; 
        }) 
        ->where(function($query) use ($searchValue) 
         { 
         if(!empty($searchValue)): 
          $query->Where('u.name','like', '%' . $searchValue . '%'); 
          $query->orWhere('u.email','like', '%' . $searchValue . '%'); 
         endif; 
        }) 
        ->where('cr.approve_status','=',1) 
        ->where('u.id','!=',$user_id) 
        ->get();

，并提供MySQL查询像这样

select `cr`.`id` as `connection_id`, `cr`.`sender_id` as `sen_id`, `cr`.`receiver_id` as `rec_id`, `cr`.`approve_status`, `u`.`id`, `u`.`user_type`, `u`.`user_type_id`, IF(u.avatar = '', 'uploads/avatar/default.jpg', u.avatar) as avatar, `u`.`name`, `u`.`email` from `connection_request` as `cr` left join `users` as `u` on `u`.`id` = `cr`.`sender_id` or `u`.`id` = `cr`.`receiver_id` where (`cr`.`receiver_id` = 10 or `cr`.`sender_id` = 10) and (`u`.`name` LIKE 'pri' or `u`.`email` LIKE 'pri') and `cr`.`approve_status` = 1 and `u`.`id` != 10

所以，我没有能够得到的结果，因为像后，它应该有%符号，但是，产生laravel查询没有百分号

我下面原始查询工作完美

select `cr`.`id` as `connection_id`, `cr`.`sender_id` as `sen_id`, `cr`.`receiver_id` as `rec_id`, `cr`.`approve_status`, `u`.`id`, `u`.`user_type`, `u`.`user_type_id`, IF(u.avatar = '', 'uploads/avatar/default.jpg', u.avatar) as avatar, `u`.`name`, `u`.`email` from `connection_request` as `cr` left join `users` as `u` on `u`.`id` = `cr`.`sender_id` or `u`.`id` = `cr`.`receiver_id` where (`cr`.`receiver_id` = 10 or `cr`.`sender_id` = 10) and (`u`.`name` LIKE '%pri%' or `u`.`email` LIKE '%pri%') and `cr`.`approve_status` = 1 and `u`.`id` != 10

请检查和帮助我的家伙，

感谢

来源

2017-06-07 Saravanan Nandhan

Where！= where where？ – Kyslik

您使用的是什么版本的Laravel？ – Jerodev

就个人而言，我使用的，它的工作原理相当好...

$query->where('u.name','LIKE', "%{$searchValue}%")->get();

来源

2017-06-07 09:46:25 Smo

你在那里的条件也可以是这样的.. 它会运行

->where(function($query) use ($searchValue) 
         { 
         if(!empty($searchValue)): 
         $query->Where('u.name','like', DB::raw("'%$searchValue%'")); 
         $query->orWhere('u.email','like', DB::raw("'%$searchValue%'")); 
         endif; 
        })

来源

2017-06-07 09:35:39 Jagadeesh

laravel like query is not working？

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