Spring Data with Integration Test OneToMany ManyToOne

Question

我知道这个话题并不新鲜，但是我花了几天的时间尝试解决任务。 我有3个课程 - 客户，帐户和发票。 客户有很多Accoutns，帐户有很多发票。 我映射他们：
客户

@Entity 
@Table(name = "CLIENT") 
public final class Client implements Serializable { 
... 
    @Column(length = 36, nullable = false, unique = true, updatable = false) 
    private String uuid; 

    @OneToMany(mappedBy = "client", cascade = CascadeType.ALL) 
    private List<Account> accounts; 
... 
} 

帐户

@Entity 
@Table(name = "ACCOUNT") 
public final class Account implements Serializable { 
... 
    @ManyToOne 
    @JoinColumn(name = "client_uuid", referencedColumnName = "uuid", nullable = false) 
    private Client client; 

    @OneToMany(mappedBy = "account", cascade = CascadeType.ALL) 
    private List<Invoice> invoices; 
... 
} 

发票

@Entity 
@Table(name = "INVOICE") 
public final class Invoice implements Serializable { 
    @ManyToOne 
    @JoinColumn(name = "account_uuid", referencedColumnName = "uuid", nullable = false) 
    private Account account; 
} 

我使用Spring数据JPA：

@Repository 
public interface SpringDataClientRepository extends ClientRepository, JpaRepository<Client, Integer> { 

其他相同。

当我尝试运行ITests，测试与客户端做工精细：

@RunWith(SpringJUnit4ClassRunner.class) 
@ContextConfiguration(classes = { JpaConfig.class, ITDaoConfig.class }) 
public class ITClientRepository { 
private static final Logger log = Logger.getLogger(ITClientRepository.class); 

@Autowired 
private ClientRepository clientRepository; 

@Test 
@Transactional 
public void testSaveClient() { 
log.info("testSaveClient start"); 

Client client = new Client(); 
client.setName("testSaveClient"); 
client.setUuid("client-testSaveClient"); 
client.setTelephone("12345679"); 

Account account = new Account(); 
account.setClient(client); 
account.setMoneyCount(10); 
account.setUuid("client-testSaveClient"); 
client.addAccount(account); 

log.info(client.toString()); 
Client getClient = clientRepository.save(client); 
log.info(client.toString()); 

它节省了客户和帐户，但该测试：

@RunWith(SpringJUnit4ClassRunner.class) 
@ContextConfiguration(classes = { JpaConfig.class, ITDaoConfig.class }) 
public class ITAccountRepository { 
    private static final Logger log = Logger.getLogger(ITAccountRepository.class); 

    @Autowired 
    private AccountRepository accountRepository; 

    @Test 
    @Transactional 
    public void testSaveAccount() { 
    log.info("testSaveAccount start"); 

    Client client = new Client(); 
    client.setName("testSaveAccount"); 
    client.setTelephone("12345679"); 
    client.setUuid("account-testSaveAccount"); 
    client.setId(200); 
    // Client saved in db 

    Account account = new Account(); 
    account.setClient(client); 
    account.setMoneyCount(15); 
    account.setUuid("account-testSaveAccount"); 
    client.addAccount(account); 

    Invoice invoice = new Invoice(); 
    invoice.setAccount(account); 
    invoice.setAmount(11); 
    Date date = new Date(); 
    invoice.setCreated(date); 
    invoice.setUuid("account-testSaveClient"); 
    invoice.setDescription("Description of invoice"); 
    account.addInvoice(invoice); 

    log.info(account.toString()); 
    Account getAccount = accountRepository.save(account); 
    log.info(account.toString()); 

失败：

Caused by: org.hibernate.TransientPropertyValueException: Not-null property references a transient value - transient instance must be saved before current operation : projects.model.Invoice.account -> projects.model.Account 

我想要所有发票将被保存，如果我保存帐户这些发票。客户端也一样 - 如果我保存它们的客户端，所有帐户都将被保存。
我该怎么做？

Answer 1

我做单向接法和组成：
客户

@Entity 
@Table(name = "CLIENT") 
public final class Client extends BaseEntity { 
    @Column(length = 36) 
    private String uuid; 

    @OneToMany(cascade = CascadeType.ALL, orphanRemoval = true, fetch = FetchType.LAZY) 
    @JoinColumn(name = "client_id", referencedColumnName = "id") 
    private List<Account> accounts; 
} 

发票

@Entity 
@Table(name = "INVOICE") 
public final class Invoice extends BaseEntity { 
    @Column(length = 36) 
    private String uuid; 
} 

帐户

@Entity 
@Table(name = "ACCOUNT") 
public final class Account extends BaseEntity { 
    @Column(length = 36) 
    private String uuid; 

    @OneToMany(cascade = CascadeType.ALL, orphanRemoval = true, fetch = FetchType.LAZY) 
    @JoinColumn(name = "account_id", referencedColumnName = "id") 
    private List<Invoice> invoices; 
} 

在测试我留下的所有东西都是这样。一切正常