我试图在Java中创建一个XMPP测试客户端,我想插入到我的代码中,它的行为与真正的xmpp客户端类似,但会输出消息,例如记录到日志中。我试图做到这一点,因为我想在现实的环境或接近的环境中进行测试。创建测试XMPP客户端进行测试
理想情况下,我不想模拟或存根,因为我想要一个xmpp客户端运行。
任何想法?
我试图在Java中创建一个XMPP测试客户端,我想插入到我的代码中,它的行为与真正的xmpp客户端类似,但会输出消息,例如记录到日志中。我试图做到这一点,因为我想在现实的环境或接近的环境中进行测试。创建测试XMPP客户端进行测试
理想情况下,我不想模拟或存根,因为我想要一个xmpp客户端运行。
任何想法?
这将帮助你发送消息给xmpp上的接收者。 记得ü将不得不配置的Openfire运行此
import org.jivesoftware.smack.Chat;
import org.jivesoftware.smack.ChatManager;
import org.jivesoftware.smack.ConnectionConfiguration;
import org.jivesoftware.smack.MessageListener;
import org.jivesoftware.smack.XMPPConnection;
import org.jivesoftware.smack.XMPPException;
import org.jivesoftware.smack.packet.Message;
import org.jivesoftware.smack.packet.Presence;
public class SenderTest
{
public static void main(String args[])
{
//ConnectionConfiguration connConfig = new ConnectionConfiguration("localhost", 5222);
//connConfig.setSASLAuthenticationEnabled(false);
ConnectionConfiguration connConfig = new ConnectionConfiguration("localhost", 5222);
//ConnectionConfiguration connConfig = new ConnectionConfiguration("talk.google.com", 5222, "gmail.com");
XMPPConnection connection = new XMPPConnection(connConfig);
try {
connection.connect();
System.out.println("Connected to " + connection.getHost());
} catch (XMPPException ex) {
//ex.printStackTrace();
System.out.println("Failed to connect to " + connection.getHost());
System.exit(1);
}
try {
connection.login("[email protected]", "a");
System.out.println("Logged in as " + connection.getUser());
Presence presence = new Presence(Presence.Type.available);
connection.sendPacket(presence);
} catch (XMPPException ex) {
//ex.printStackTrace();
System.out.println("Failed to log in as " + connection.getUser());
System.exit(1);
}
ChatManager chatmanager = connection.getChatManager();
Chat newChat = chatmanager.createChat("[email protected]", new MessageListener() {
public void processMessage(Chat chat, Message message) {
System.out.println("Received message: " + message);
}
});
try {
newChat.sendMessage("Howdy!");
System.out.println("Message Sent...");
}
catch (XMPPException e) {
System.out.println("Error Delivering block");
}
}
}
谢谢,我也开始在tigase寻找热塑成型之前,创建一个嵌入式XMPP sevrer在我的应用程序..我努力尝试运行它作为即时通讯发现它非常棘手。 – Iqbal 2012-08-02 14:01:02