使用以下代码:当我用g ++编译器编译C++时,错误是什么意思?
#include<iostream>
#include<vector>
using namespace std;
int main()
{
vector<int> ivec;
for(vector<int>::size_type ix = 0; ix != 10; ix++)
{
ivec.push_back(ix);
}
vector<int>::iterator mid = (ivec.begin() + ivec.end())/2;
cout << *mid << endl;
return 0;
}
获得带有克++编译一个错误:
iterator_io.cpp: In function `int main()':
iterator_io.cpp:13: error: no match for 'operator+' in '(&ivec)->std::vector<_Tp, _Alloc>::begin [with _Tp = int, _Alloc = std::allocator<int>]() + (&ivec)->std::vector<_Tp, _Alloc>::end [with _Tp = int, _Alloc = std::allocator<int>]()'
/usr/lib/gcc/x86_64-redhat-linux/3.4.5/../../../../include/c++/3.4.5/bits/stl_iterator.h:654: note: candidates are: __gnu_cxx::__normal_iterator<_Iterator, _Container> __gnu_cxx::__normal_iterator<_Iterator, _Container>::operator+(const typename std::iterator_traits<_Iterator>::difference_type&) const [with _Iterator = int*, _Container = std::vector<int, std::allocator<int> >]
/usr/lib/gcc/x86_64-redhat-linux/3.4.5/../../../../include/c++/3.4.5/bits/stl_bvector.h:261: note: std::_Bit_iterator std::operator+(ptrdiff_t, const std::_Bit_iterator&)
/usr/lib/gcc/x86_64-redhat-linux/3.4.5/../../../../include/c++/3.4.5/bits/stl_bvector.h:345: note: std::_Bit_const_iterator std::operator+(ptrdiff_t, const std::_Bit_const_iterator&)
/usr/lib/gcc/x86_64-redhat-linux/3.4.5/../../../../include/c++/3.4.5/bits/stl_iterator.h:765: note: __gnu_cxx::__normal_iterator<_Iterator, _Container> __gnu_cxx::operator+(typename __gnu_cxx::__normal_iterator<_Iterator, _Container>::difference_type, const __gnu_cxx::__normal_iterator<_Iterator, _Container>&) [with _Iterator = int*, _Container = std::vector<int, std::allocator<int> >]
我知道ivec.end()不能被用作通常的向量元素。但我不明白什么是错误信息意味着...关于operator +的一些东西?
对于一个问题很好,格式良好,标记正确的第一个问题,+1。 – razlebe 2012-03-13 13:26:32
+1包括一个简短的完整样本程序。 http://sscce.org/ – 2012-03-13 13:28:15