preg_replace一切：文本和换行符

Question

我有一个文本，只是想删除我的第一次捕获后的一切。我发现我重复“\ s”至少和我有换行符一样多。但我希望有一个更灵活和干燥的解决方案。

$subject = "SomeText()         asaas 
DFDFDFD 

dsdsds 

dsdsds"; 
$pattern = "#\).*\s*.*\s*.*\s*.*#" ; 
$replacement = ")"; 
$newText = preg_replace($pattern, $replacement, $subject); 
Utils_Echo::myEcho($subject); 
Utils_Echo::myEcho($newText); 


$pattern = "#\)[.\s]*#"; //I hoped something like this would work but it could not figure it out. Can you show me a way? 

Answer 1

从有序最快到最慢：

没有正则表达式：最明显

$newText = (false !== $pos = strpos($subject, ')')) ? substr($subject, 0, $pos + 1) 
                 : $subject; 

随着preg_match：把你想要的东西，而不是代替你做什么不想要

$newText = preg_match('~[^)]*\)~', $subject, $m) ? $m[0] : $subject; 

随着preg_replace：S修正允许点以匹配换行符

$newText = preg_replace('~\).*~s', ')', $subject);