2014-12-13 139 views
2

我正在java中使用正则表达式提取日期提取器。问题是这个日期是20-05-2014,我的程序正在提取0-5-14。总之,我怎么能得到我在检查日期的第二个字符的角色?正则表达式:如何包含“如果”条件的字符

int count = 0; 
    String data = "HellowRoldsThisis20-05-2014. [email protected]@gmail.com"; 
    String regexOfDate = "((?<=[0])[1-9]{2})|((?<=[12])[0-9])|((?<=[3])[01])\\.\\-\\_((?<=[0])[1-9])|((?<=[1])[0-2])\\.\\-\\_((?<=[2])[0-9]{4})"; \\THE PROBLEM 
    String[] extractedDate = new String[1000]; 
    Pattern patternDate = Pattern.compile(regexOfDate); 
    Matcher matcherDate = patternDate.matcher(data); 

    while(matcherDate.find()){   
     System.out.println("Date "+count+"Start: "+matcherDate.start()); 
     System.out.println("Date "+count+"End : "+matcherDate.end()); 
     extractedDate[count] = data.substring(matcherDate.start(), matcherDate.end()); 
     System.out.println("Date Extracted: "+extractedDate[count]); 
    } 

回答

2

您可以尝试正则表达式:

// (0[1-9]|[12][0-9]|[3][01])[._-](0[1-9]|1[0-2])[._-](2[0-9]{3}) 
"(0[1-9]|[12][0-9]|[3][01])[._-](0[1-9]|1[0-2])[._-](2[0-9]{3})" 

Debuggex

+0

如何绘制正则表达式? – Kyslik 2014-12-13 18:58:21

0

单一的正则表达式匹配Ø有效日期是awful

我会怎么做:

String regexOfDate = "(?<!\\d)\\d{2}[-_.]\\d{2}[-_.]\\d{4}(?!\\d)"; 

提取潜在的日期,然后测试,如果它是有效的。

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