过滤嵌套关系Django的REST框架

我有两个型号，看起来像下面这样：过滤嵌套关系Django的REST框架

class Subject(models.Model): 

    subject_code = models.CharField(max_length=12, unique=True) 
    name = models.CharField(max_length=100) 
    dept_code = models.CharField(max_length=6)

和...

class Subject_assessment(models.Model):  
    subject_code = models.ForeignKey(Subject, related_name='sub_assessments') 
    year = models.CharField(max_length=4) 
    name = models.CharField(max_length=50)

我已经创建了我的连载以这样的方式，当我找回一个主题，我也检索与该主题相关的评估。我使用下面的序列化来实现：

class AssessmentsSerializer(serializers.ModelSerializer): 
class Meta: 
    model = Subject_assessment 
    fields = (
     "subject_code", "year", "name" 
    ) 

class SubjectSerializer(serializers.ModelSerializer): 
sub_assessments = AssessmentsSerializer(many=True) 
class Meta: 
    model = Subject 
    fields = (
     "subject_code", "name", "dept_code",    
     "sub_assessments" 
    )

此代码工作完全如预期，因为它给了我这样的结果：

{ 
"subject_code":"ECR2243", 
"name":"Statistics", 
"dept_code":"Stats", 
"sub_assessments":[ 
    { 
     "subject_code":"ECR2243", 
     "year":"2017", 
     "name":"Test 1" 
    }, 
    { 
     "subject_code":"ECR2243", 
     "year":"2016", 
     "name":"Test 1" 
    } 
] 
}

我的问题是，我希望检索评估只针对特定的一年。例如，如果我作为感兴趣的年份通过，我不希望像我目前正在获取的那样检索评估。

任何人都可以请协助我如何构建我的代码，以完成此任务。先谢谢你。

编辑1 我views.py如下：

class SubjectViewSet(viewsets.ModelViewSet): 
serializer_class = SubjectSerializer 
lookup_field = 'subject_code' 

def get_queryset(self): 
    qry_subject_code = self.request.GET.get('subject_code') 
    retrieved_sub = Subject.objects.filter(subject_code=qry_subject_code) 
    return retrieved_sub

来源

2017-02-10 Tatenda

你能扩大与view.py – marin

检查你的问题http://www.django-rest-framework.org/api-guide/serializers/#additional-keyword-arguments 。它详细介绍了如何将额外参数传递给序列化程序。它可以帮助您构建解决方案。 –

@marin我已添加我的views.py – Tatenda

这是为我工作的解决方案这个问题：

class FilteredAssessmentsSerializer(serializers.ListSerializer): 
    def to_representation(self,data): 
     qry_year = self.context['request'].GET.get('year') 
     data = data.filter(year=qry_year) 
     return super(FilteredAssessmentsSerializer, self).to_representation(data) 

class AssessmentsSerializer(serializers.ModelSerializer): 
    class Meta: 
     model = Subject_assessment 
     list_serializer_class = FilteredAssessmentsSerializer 
     fields = '__all__' 

class SubjectSerializer(serializers.ModelSerializer): 
    sub_assessments = AssessmentsSerializer(many=True) 
    class Meta: 
     model = Subject 
     fields = (
      "subject_code", "name", "dept_code", 
      "faculty_code", "university_code", "description", 
      "sub_assessments" 
     )

参考：我结合以下解决方案来想出一个适合我的。

How can I apply a filter to a nested resource in Django REST framework?

https://stackoverflow.com/a/28354281/7210105

来源

2017-02-11 15:29:49 Tatenda

你可以尝试用此查询：

retrieved_sub = Subject_assessment.objects.filter(subject_code__in=Subject.objects.filter(subject_code=qry_subject_code),year='2014').all()

来源

2017-02-10 10:59:01 marin

不工作。（）在那里的原因是什么？ – Tatenda

你可以在打电话给URL时打印＃retrieve_sub＃吗？因为.all（）将返回查询中的所有值。 – marin

不知道你是否正确地得到我的问题。我的代码是从数据库返回结果，检查问题。我的问题是如何筛选嵌套序列化器的结果到 – Tatenda

过滤嵌套关系Django的REST框架

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