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下面的程序是为了遍历holiday_hash,利用所有键和值,并把他们出去:Ruby程序没有按预期执行?如果块执行,尽管失败的情况
def all_supplies_in_holidays(holiday_hash)
holiday_hash.each do |key, value|
key_string = key.to_s
key_string.capitalize!
puts "#{key_string}:"
value.each do |key2, value2|
if key2 == :new_year || :fourth_of_july || :memorial_day
key_to_string = key2.to_s
key_string1 = key_to_string.split
final_array = []
key_string1.each do |splitted_string|
final_array = splitted_string.capitalize!
end
final_string = final_array.join(" ")
print "#{final_string1}:"
else
key_string1 = key2.to_s
print "#{key_string1}"
end
value2.each do |array_value|
new_array_capitalized = []
new_array_capitalized << array_value.capitalize!
new_array.join(" ")
end
end
end
end
预期的输出格式为:
Winter:
Christmas: Lights, Wreath
New Years: Party Hats
Summer:
Fourth of July: Fireworks, BBQ
Fall:
Thanksgiving: Turkey
Spring:
Memorial Day: BBQ
该holiday_hash如下:
{
:winter => {
:christmas => ["Lights", "Wreath"],
:new_years => ["Party Hats"]
},
:summer => {
:fourth_of_july => ["Fireworks", "BBQ"]
},
:fall => {
:thanksgiving => ["Turkey"]
},
:spring => {
:memorial_day => ["BBQ"]
}
}
的问题是:
- 即使条件未能评估为true,if块也会执行。
建议需要:
- 我怎么能简化资本谁在他们两个单词符号的过程,如:new_york资本化到纽约? (由于#capitalised方法将返回纽约)
好吧..但为什么呢?我不知道发生了什么事。我现在更加困惑..很抱歉,这不是因为你的回答,而是你刚刚指出的事实。你能否进一步解释为什么会发生这种情况? –
@ZeeshanShafqat对不起,我还在写我的答案,再次检查。 – Stefan