在Python中解析来自http请求的文本响应

Question

我试图从APU中获取数据，但作为响应，我正在获取纯文本。我想逐行读取所有文本。

这是url变量：http://www.amfiindia.com/spages/NAVAll.txt?t=23052017073640

第一个片段：

from pymongo import MongoClient 
import requests 
from bs4 import BeautifulSoup as bs 
url = "https://www.amfiindia.com/spages/NAVAll.txt?t=23052017073640" 
request = requests.get(url) 
soup = bs(request.text,"lxml") 
for line in soup: 
    print line 
    break 

结果：它打印出整个文本

二片段：

request = requests.get(url) 
for line in request.text(): 
    print line 
    break 

结果：它打印出1个字符

request = requests.get(url) 
requestText = request.text() 
allMf = requestText.splitlines() 

结果：异常：

我已经试过几个案件，但不能按行读取文本行“的Unicode”对象不是可调用的。

Answer 1

request.text是一个属性而不是一个方法，request.text返回一个unicode字符串，request.text()抛出错误'unicode' object is not callable。

for line in request.text.splitlines(): 
    print line 

Answer 2

试试这个：

from pymongo import MongoClient 
import requests 
from bs4 import BeautifulSoup as bs 
url = "https://www.amfiindia.com/spages/NAVAll.txt?t=23052017073640" 
request = requests.get(url) 
soup = bs(request.text,"lxml") 
for line in soup: 
    print line.text 
    break 

Answer 3

import requests 
from bs4 import BeautifulSoup as bs 
url = "https://www.amfiindia.com/spages/NAVAll.txt?t=23052017073640" 
request = requests.get(url) 
soup = bs(request.text,"lxml") 

# soup.text is to get the returned text 
# split function, splits the entire text into different lines (using '\n') and stores in a list. You can define your own splitter. 
# each line is stored as an element in the allLines list. 
allLines = soup.text.split('\n') 

for line in allLines: # you iterate through the list, and print the single lines 
    print(line) 
    break # to just print the first line, to show this works