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我试图做一个使用画布作为任务的js游戏。我应该在画布上绘制蚂蚁,他们应该去寻找食物。我的代码可以扩展。出于某种原因,只有一个错误去食物,但真正的问题是,吃了两个食物后,当蚂蚁走第三时,js只是崩溃。计时器停止,我的按钮停止工作。我真的很困惑,不知道为什么它这样做。林调用requestAnimationFrame移动蚂蚁和我保持通话移动它们的功能是这样的:JS在Chrome上崩溃
function repeatOften() {
var cur_time = Date.now();
var delta_time = (cur_time - last_frame)/1000;
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
ctx.clearRect(0, 0, canvas.width, canvas.height);
//ctx.fillRect(0, 0, canvas.width, canvas.height);
//update each bug
for (var i = 0; i < bugArray.length; i++) {
if (foodArray.length != 0) {
bugArray[i].cur_target = foodArray[0];
var shortest_dist = Math.sqrt(((foodArray[0].xpos - bugArray[i].xpos) * (foodArray[0].xpos - bugArray[i].xpos)) + ((foodArray[0].ypos - bugArray[i].ypos) * (foodArray[0].ypos - bugArray[i].ypos)));
for (var a = 0; a < foodArray; a++) {
if (Math.sqrt(((foodArray[a].xpos - bugArray[i].xpos) * (foodArray[a].xpos - bugArray[i].xpos)) + ((foodArray[a].ypos - bugArray[i].ypos) * (foodArray[a].ypos - bugArray[i].ypos))) < shortest_dist) {
bugArray.cur_target = foodArray[a];
shortest_dist = Math.sqrt(((foodArray[a].xpos - bugArray[i].xpos) * (foodArray[a].xpos - bugArray[i].xpos)) + ((foodArray[a].ypos - bugArray[i].ypos) * (foodArray[a].ypos - bugArray[i].ypos)));
}
}
// go towards the cur_target
if ((((bugArray[i].xpos - bugArray[i].cur_target.xpos) >= 0) && ((bugArray[i].xpos - bugArray[i].cur_target.xpos) < 10)) && (((bugArray[i].ypos - bugArray[i].cur_target.ypos) >= 0) && ((bugArray[i].ypos - bugArray[i].cur_target.ypos) < 10))) {
removeFood(bugArray[i].cur_target);
}
if ((bugArray[i].xpos - bugArray[i].cur_target.xpos) > 0) {
bugArray[i].xpos -= bugArray[i].speed * delta_time;
} else if ((bugArray[i].xpos - bugArray[i].cur_target.xpos) < 0) {
bugArray[i].xpos += bugArray[i].speed * delta_time;
}
if ((bugArray[i].ypos - bugArray[i].cur_target.ypos) > 0) {
bugArray[i].ypos -= bugArray[i].speed * delta_time;
} else if ((bugArray[i].ypos - bugArray[i].cur_target.ypos) < 0) {
bugArray[i].ypos += bugArray[i].speed * delta_time;
}
}
//draw foods
for (var i = 0; i < foodArray.length; i++) {
drawFood(foodArray[i]);
}
}
//update time
time -= delta_time;
last_frame = cur_time;
var timespan = document.getElementById("time");
timespan.innerHTML = Math.round(time) + " seconds";
if (Math.round(time) == 0 || foodArray.length == 0) {
DisplayScore();
pause();
} else {
drawBugArray();
GlobalID = requestAnimationFrame(repeatOften);
if (Math.round(time) % ((Math.round(Math.random() * 300) + 1)) == 0) {
spawnBug();
}
}
}
我drawfood和drawbugarray功能只是在画布上绘制的食物和错误的模板,我的去除食物的功能是作为如下:
function removeFood(food) {
for (var i = 0; i < foodArray.length; i++) {
if (foodArray[i] == food) {
var temp = foodArray[i];
foodArray[i] = foodArray[foodArray.length - 1];
foodArray.pop();
return temp;
}
}
}
我真的很感谢任何帮助!预先感谢您:)
不应该是for (var a = 0; a
多数民众赞成在正确的感谢:D但没有导致问题 –
打开Javascript调试器,并在它即将崩溃时单击暂停按钮,以便您可以看到代码卡住的位置。 – Barmar