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此php代码通过javascript中的ajax调用，并应返回数字代码和消息。我可以从PHP脚本中返回一个数组，但是当我读取ajax响应时，响应包含的不止是返回的数组，它还有其他的回显语句。有没有办法从Php发送只有返回数组的信息？我只想要json对象{"return_code":0,"return_msg":"Login successful."}。带返回码和返回信息的PHP函数用于信息目的
这是通过ajax返回给javascript的信息alert(login_info);。
Warning: date(): It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or thedate_default_timezone_set（）函数。如果您使用这些 方法中的任何一种，并且您仍然收到此警告，则极有可能是 拼写错误时区标识符。我们选择'America/New_York'作为 'EDT/-4.0/DST'而不是 /Library/WebServer/Documents/Pagelinks_Dev/login_user.php on line 60 {“return_code”：0，“return_msg”：“登录成功“}
这是ajax调用。
var message = $.ajax({
url: "login_user.php",
type: "POST",
data: { username_email: username_email, upass: user_passwd },
cache: false,
async: false,
success: function (login_info) {
if (login_info != '')
{
alert(login_info);
}
},
error: function (request, status, error) {
alert ("status "+status+" error "+error+"responseText "+request.responseText);
},
}).responseText;
PHP脚本
<?php include("dbconnect.php"); ?>
<?php
ini_set('display_errors', 1);
error_reporting(E_ALL);
session_start();
function login_user($username_email, $password_text) {
global $dbco;
$password = md5($password_text);
$privPost = 1; // 3: max.
$privSedit = 0;
$messages = array('log_no_un_em' => 'Enter username or email.',
'log_no_pw' => 'Enter password.',
'log_un_em_pw_incorrect' => 'Incorrect login info.',
'log_success' => 'Login successful.'
);
$return = array();
$l_un_em = isset($username_email) ? $username_email : '';
$l_pword = isset($password_text) ? $password_text : '';
if (!$l_un_em) {
/* echo $messages['log_no_un_em'];
return; */
$return['return_code'] = -1;
$return['return_msg'] = $messages['log_no_un_em'];
echo json_encode($return);
}
if (!$l_pword) {
/* echo $messages['log_no_pw'];
return; */
$return['return_code'] = -1;
$return['return_msg'] = $messages['log_no_pw'];
echo json_encode($return);
}
mysql_select_db("luxcal", $dbco);
while (true) {
$md5_pw = md5($password_text);
$r_getuser = mysql_query("SELECT * FROM users WHERE (user_name = BINARY '".mysql_real_escape_string($l_un_em)."' OR email = '".mysql_real_escape_string($l_un_em)."') AND (password = '$md5_pw' OR temp_password = '$md5_pw') AND status >= 0");
if (mysql_num_rows($r_getuser) == 0) {
/* echo $messages['log_un_em_pw_incorrect'];
return; */
$return['return_code'] = -1;
$return['return_msg'] = $messages['log_un_em_pw_incorrect'];
echo json_encode($return);
}
$row = mysql_fetch_assoc($r_getuser);
/* if ($row['privs'] < 1) { echo $messages['log_no_privs']; break; } */
if ($row['temp_password'] == $md5_pw) { //new password
mysql_query("UPDATE users SET password = '".$md5_pw."', temp_password = NULL WHERE user_id = '{$row['user_id']}'");
}
$today = date('Y-m-d');
if ($row['login_0'][0] == '9') { //first login
mysql_query("UPDATE users SET login_0 = '".$today."', login_1 = '".$today."', login_cnt = 1 WHERE user_id = '{$row['user_id']}'");
} else {
mysql_query("UPDATE users SET login_1 = '".$today."', login_cnt = login_cnt+1 WHERE user_id = '{$row['user_id']}'");
}
$_SESSION['uid'] = $row['user_id'];
$_SESSION['unm'] = stripslashes($row['user_name']);
$_SESSION['uml'] = stripslashes($row['email']);
$_SESSION['cL'] = $row['language'];
/* echo '<meta http-equiv="refresh" content="0;url=livemass_CENTER34.php">'; */ //default page
break;
}
$return['return_code'] = 0;
$return['return_msg'] = $messages['log_success'];
echo json_encode($return);
/* return; */
}
echo login_user(trim($_REQUEST['username_email']), trim($_REQUEST['upass']));
?>
'async：false' - ** BAD **。特别是对于使用同步请求登录等简单事情来说，这是完全不必要的和错误的。 – ThiefMaster 2012-04-21 19:22:47
我会在SO上发布之前阅读警告。它清楚地说使用['date_default_timezone_set（）']（http://php.net/manual/en/function.date-default-timezone-set.php）来设置时区，因为它认为你不应该依赖其默认值。如果您不了解该警告，请尝试使用谷歌搜索的一部分。你可能不是第一个体验过它的人。 – 2012-04-21 19:24:27
我想不出一种比您在问题中发布的PHP警告中提供的更好的答案。 – Hamish 2012-04-21 19:34:37