解散后重新显示对话框

Question

如何在每次关闭后重新显示相同的对话框？ 我的代码（在科特林）：

val alertDialog = AlertDialog.Builder(this) 
alertDialog.setMessage(getString(R.string.alert_dialog_main_activity)) 
val editText = EditText(this) 
editText.inputType = InputType.TYPE_CLASS_PHONE 
alertDialog.run { 
    setView(editText) 
    setOnDismissListener { TODO("Re-show dialog" } 
    setPositiveButton("Done", { dialogInterface, i -> 
     run { 
      toast(editText.text.toString()) 
      PreferenceManager.getDefaultSharedPreferences(applicationContext).edit().putInt("phoneNumber", editText.text.toString().toInt()).commit() 
      } 
     }) 
    show() 
} 

答案可能是在Java中了。

Answer 1

试试这个：

AlertDialog.Builder(this).apply { 
    setMessage(getString(R.string.alert_dialog_main_activity)) 
    setView(editText) 
    setOnDismissListener { 
     if(/*TODO validate phone number*/) 
     (it as AlertDialog).show() 
    } 
    setPositiveButton("Done", { dialogInterface, i -> 
     toast(editText.text.toString()) 
     PreferenceManager.getDefaultSharedPreferences(applicationContext).edit().putInt("phoneNumber", editText.text.toString().toInt()).commit() 

    }) 
    show() 
} 

Answer 2

最简单的方法是可能记得显示对话的功能，如：

fun showDialog() { 
     val alertDialog = AlertDialog.Builder(this) 
     alertDialog.setMessage(getString(R.string.alert_dialog_main_activity)) 
     val editText = EditText(this) 
     editText.inputType = InputType.TYPE_CLASS_PHONE 
     alertDialog.run { 
      setView(editText) 
      setOnDismissListener { 
       showDialog() // recall the function 
      } 
      setPositiveButton("Done", { dialogInterface, i -> { 
        toast(editText.text.toString()) 
        PreferenceManager.getDefaultSharedPreferences(applicationContext).edit().putInt("phoneNumber", editText.text.toString().toInt()).commit() 
        } 
       }) 
      show() 
     } 
    }