我使用MS SQL服务器2014年
我有一个表值函数
ALTER FUNCTION [dbo].[Resultsaddresssearch](@addressLine nvarchar, @locality nvarchar, @adminDistrict nvarchar, @postalCode nvarchar, @countryRegion nvarchar) RETURNS TABLE ( [Name] nvarchar NULL, [Point] [geography] NULL, [BoundingBox] [geography] NULL ) WITH EXECUTE AS CALLER AS EXTERNAL NAME [xtest2].[addresssearch.UserDefinedFunctions].[GeocodeTVF]
从查询导出的数据结果
,我用这个查询 SELECT * FROM dbo.Resultsaddresssearch('999 NE 10th%', '', '', '', 'USA');
结果我想出口到预先配置的csv,它是addy,csv。当我使用导出管理器时,我选择了sql本机客户端11作为源。然后选择平面文件作为目的地。我从上面输入查询并点击下一步,我得到这个错误:
- Column "Point": Source data type "204" was not found in the data type mapping file.
- Column "BoundingBox": Source data type "204" was not found in the data type mapping file.
感谢