我想让我的种子工作尽可能小,并将所有逻辑保存在中央git存储库中。此外,我有几个独立的Jenkins实例,然后可以共享代码。如何在Jenkins Job DSL脚本中加载Groovy库?Jenkins Job DSL - 从git repo加载groovy库
是否有像Pipeline Remote File Loader Plugin这样的东西,所以你只需要做fileLoader.fromGit('lib.groovy', 'https://git.repo')
?
我想让我的种子工作尽可能小,并将所有逻辑保存在中央git存储库中。此外,我有几个独立的Jenkins实例,然后可以共享代码。如何在Jenkins Job DSL脚本中加载Groovy库?Jenkins Job DSL - 从git repo加载groovy库
是否有像Pipeline Remote File Loader Plugin这样的东西,所以你只需要做fileLoader.fromGit('lib.groovy', 'https://git.repo')
?
此后我对从git.repo在参数化流水线作业实现这一目标, 使用管道脚本SCM的Quicksheet
可能是什么你的兴趣:
stash/unstash
src = "../${env.JOB_NAME}@script/"
个詹金斯
Pipeline
Definition: "Pipeline script from SCM"
SCM: Git
Repository URL git.repo
Branches to build */master
Script Path jobs/build.groovy
This project is parameterized:
String Parameter PARAM0
String Parameter PARAM1
git.repo
├── jobs
│ ├── helpers
│ │ └── utils.groovy
│ └── build.groovy
└── scripts
├── build
│ └── do_build.sh
└── inc.sh
内容:utils.groovy
├── jobs
│ ├── helpers
│ │ └── utils.groovy
def log(msg) {
println("========== " + msg)
}
return this
内容:build.groovy
├── jobs
│ └── build.groovy
stage ('Init') {
/* Loads */
def src = "../${env.JOB_NAME}@script/"
def helpers_dir = 'jobs/helpers'
def scripts_dir = 'scripts'
/* Stages Scripts */
def do_build = 'build/do_build.sh'
utils = load src + helpers_dir + "/utils.groovy"
dir(src) {
stash name: scripts_dir, includes: "${scripts_dir}/"
}
}
stage ('Build') {
node() {
unstash scripts_dir
build_return = sh (returnStdout: true, script: """
./${scripts_dir}/${do_build} \
"${PARAM0}" \
"${PARAM1}"
""").readLines()
builded = build_return.get(build_return.size()-1).tokenize(',')
utils.log("PARAM0: " + builded[0])
utils.log("PARAM1: " + builded[1])
}
}
项内容:inc.sh
└── scripts
└── inc.sh
#!/bin/sh
## scripts common includes
common=included
内容:do_build.sh
└── scripts
├── build
│ └── do_build.sh
#!/bin/sh
## includes
. $(dirname $(dirname ${0}))/inc.sh
echo ${common}
## ${0} : PARAM0
## ${1} : PARAM1
echo "${0},${1}"
的Job DSL Gradle Example展示了如何保持DSL代码在一个Git仓库。