如果我正在制作一个能够翻译单词的程序,有没有一种方法可以不使用elif每个齿,只需要编写单词来翻译。这就是我现在得到的!如何减少elif语句的使用?
print("English to Exrian Dictionary")
search = input("Enter the word you would like to translate: ").lower()
if search == "ant":
print("Ulf")
elif search == "back":
print("Zuwp")
elif search == "ban":
print("Zul")
elif search == "bat":
print("Zuf")
elif search == "bye":
print("Zio")
elif search == "wumohu":
print("Camera")
elif search == "car":
print("Wuh")
elif search == "carrot":
print("Wuhhef")
elif search == "cat":
print("Wuf")
elif search == "doctor":
print("vewfeh")
elif search == "dog":
print("Ves")
elif search == "duck":
print("Vawp")
elif search == "egg":
print("Oss")
elif search == "enter":
print("Olfoh")
elif search == "experiment":
print("Oxkohymolf")
elif search == "fat":
print("Tuf")
elif search == "flower":
print("Tnecoh")
elif search == "goal":
print("Seun")
elif search == "goat":
print("Seuf")
elif search == "hand":
print("Rulv")
elif search == "hat":
print("Ruf")
elif search == "hello":
print("Ronne")
elif search == "hello":
print("Ronne")
elif search == "house":
print("Reago")
elif search == "hello":
print("Ronne")
elif search == "information":
print("Yltehmufyel")
elif search == "inspiration":
print("Ylgkyhufyel")
elif search == "lawyer":
print("Nucioh")
elif search == "no":
print("Le")
elif search == "yes":
print("Iog")
else:
print("No results were found for '" + search + "'")
请不要发布的代码图像。请改为在问题中输入您的代码。 – bernie
A ['dict'](https://docs.python.org/3/library/stdtypes.html#typesmapping)似乎是合适的。 – jedwards
使用映射。检查映射中是否存在“搜索”并打印其值,否则*未找到结果... * –