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插入我的PHP页面上奇怪的问题,我试图像这样问题在sqlite3的从PHP
$id=$db->insert_user("'".$parameters['first_name']."'", "'".$parameters['last_name']."'", "'".$parameters['email']."'", "'".$parameters['username']."'", "'".$parameters['password']."'", "'".$parameters['privilege']."'");
其中
try {
$db = new SQLite3($this->db_path);
echo "INSERT INTO users(first_name,last_name,email,username,password,privilege) VALUES('$first_name','$last_name','$email','$username','$password','$privilege');";
$db->query("INSERT INTO users(first_name,last_name,email,username,password,privilege) VALUES('$first_name','$last_name','$email','$username','$password','$privilege');");
$last_id = $db->lastInsertRowID();
echo ''.$last_id;
$db->close();
return $last_id;
} catch (Exception $e) {
echo 'Exception caught: ', $e->getMessage(), "\n";
}
INSERT INTO users(first_name,last_name,email,username,password,privilege) VALUES(''drkosh'',''drkosh'',''drkosh'',''drkosh'',''drkosh'',''ignore'');
结果中插入新行到表的用户(sqlite3的)回声是
INSERT INTO users(first_name,last_name,email,username,password,privilege) VALUES(''drkosh'',''drkosh'',''drkosh'',''drkosh'',''drkosh'',''ignore'');
错误消息是奇怪的,它说在35行,但35是在切换,我从来没有通过35,有布雷亚KS。有人有什么错误的线索吗? (所有列都OK和表名)