2011-10-31 163 views
0

我在删除内容时遇到了一些麻烦,当存在与另一个对象的多对多关系。休眠ManyToMany删除

要通过阵列每个实体进行删除我有一个名为查询的数组和删除,我循环并执行删除,实体,像这样:

private static final String[] DELETE_CONTENT_QUERY_NAMES = { 
    "Entity1.deleteByContentId", 
    "Entity2.deleteByContentId", 
    "Entity3.deleteByContentId", 
    "Entity4.deleteByContentId", 
    "Entity5.deleteByContentId", 
    "EntityWithManyToMany.deleteByContentId", 
    "Entity7.deleteByContentId", 
    "Content.DeleteByContent" 
}; 

@Override 
@Transactional 
public void deleteContent(Content content) throws Exception{ 
    Map<String, Object> params = new HashMap<String, Object>(); 
    params.put("contentId", content.getContentId()); 
    for (String queryName : DELETE_CONTENT_QUERY_NAMES) { 
     dao.batchDeleteByNamedQuery(queryName, params); 
    } 
} 

当迭代尝试执行EntityWithManyToMany.deleteByContentId HQL批量查询,我可以在日志中看到翻译后的sql指令,但后面跟着一组插入相同的行,MySQL正确地返回了我的约束错误。

这是我的多对多关系对象我试图删除:

@Entity 
@Embeddable 
public class CategoryContent implements java.io.Serializable { 

    /*** 
    * Private Declarations 
    */ 
    @EmbeddedId 
    @AttributeOverrides({ 
     @AttributeOverride(name = "contentId", column = @Column(
       name = "CONTENT_ID", 
       nullable = false, precision = 10, scale = 0)), 
     @AttributeOverride(name = "categoryId", column = @Column(
       name = "CATEGORY_ID", 
       nullable = false, precision = 10, scale = 0)) 
    }) 
    @NotNull 
    private CategoryContentId id; 

    @ManyToOne(fetch = FetchType.EAGER, cascade=CascadeType.PERSIST) 
    @JoinColumn(name = "CATEGORY_ID", insertable=false, updatable=false) 
    private Category category; 

    @ManyToOne(fetch = FetchType.EAGER, cascade=CascadeType.PERSIST) 
    @JoinColumn(name = "CONTENT_ID", insertable=false, updatable=false) 
    private Content content; 

    @Column(name = "PRIORITY", nullable = true) 
    private Integer priority; 
} 

你认为这是可能的问题关注CascadeType的?我该如何解决这个问题?

任何建议表示赞赏!

非常感谢, Davide。

回答

0

你在正确的轨道上 - 尝试修改您的级联

cascade = {CascadeType.PERSIST, CascadeType.DELETE} 

这应该工作,因为你有一个连接表。

+0

不幸的是不工作,hibernate具有相同的行为 – Davide