错误是在位置http://127.0.0.1:8000/fileupload/form.pyDjango:CSRF令牌丢失或不正确
我有django的1.3版本。我曾尝试在别人的问题中指定localhost:8000,但这不适用于我。我想要一个文件上传的形式,但我收到一个错误,form.py没有CSRF令牌。
form.py:
class UploadFileForm(forms.Form):
title = forms.CharField(max_length=50)
file = forms.FileField()
views.py:
def upload_file(request):
c = {}
c.update(csrf(request))
if (not request.user.is_authenticated()) or (request.user == None):
return HttpResponseRedirect("/?error=11")
if request.method == 'POST':
form = c['UploadFileForm'] = UploadFileForm(request.POST, request.FILES, c, context_instance=RequestContext(request))
if c['UploadFileForm'].is_valid():
handle_uploaded_file(request.FILES['file'])
return HttpResponseRedirect('/success/url/')
else:
form = c['UploadFileForm'] = UploadFileForm()
return render_to_response('fileupload/upload.html', {'form': c['UploadFileForm']})
upload.html:
{% block main_content %}
<form action="fileupload/form.py" enctype="multipart/form-data" method="POST">
{% csrf_token %}
<table>
<tr><td>Title:</td><td><input type="text" name="title" /></td></tr>
<tr><td>File:</td><td><input type="file" name="file" /></td></tr>
</table>
<input type="submit" value="Submit" class = "float_right button_input" />
</form>
{% endblock main_content %}
我很为难,请告诉我一些东西去尝试。谢谢
您已经在模板中使用了'{%csrf_token%}',所以这应该起作用。 –
加上RequestContext我得到一个类型错误__init __()得到了一个意外的关键字参数'context_instance' – user1072646
谢谢,我只是想通了。它像你说的那样添加RequestContext(request),并从if语句中删除c和context_instance =。如果你改变你的答案,包括我会标记它是正确的。 – user1072646