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是否可以更改D3中被视为“链接”的内容?我从服务器接收的JSON被设置为“节点”和“边缘”而不是“节点”和“链接”。下面是一个简单的JSON:在D3中对链接使用不同的命名约定
{
"nodes": [
{"fixed":true,"data": {"id": "foo","idType":"USERNAME","color":"red"},"selected":false},
{"fixed":true,"data": {"id": "bar","idType":"USERNAME","color":"yellow"},"selected": false}
],
"edges": [
{"classes":null,"data":{"color":"blue","source":"foo","target":"bar","visible":true},"grabbable":false},
{"classes":null,"data":{"color":"green","source":"bar","target":"foo","visible":true},"grabbable":false}
]}
起初我还以为它是从
var link = svg.selectAll(".link"),
node = svg.selectAll(".node");
宣布然而当我改变.link
到.edge
我的代码中断。
// sets the source and target to use id instead of index
var edges = [];
root.edges.forEach(function(e) {
var sourceNode = root.nodes.filter(function(n) {
return n.data.id === e.data.source;
})[0],
targetNode = root.nodes.filter(function(n) {
return n.data.id === e.data.target;
})[0];
// push the attributes in the JSON to the edges.
edges.push({
source: sourceNode,
target: targetNode,
label: e.data['label'],
color: e.data['color']
});
});
force
.nodes(root.nodes)
.links(edges)
.start();
link = link
.data(edges)
.enter().append("line")
.attr("class", "link")
.style("stroke-width", 1.5);
node = node
.data(root.nodes)
.enter().append("g")
.attr("class", "node");
我认为它不重要什么d3称它。你如何初始化你的图表? – Halcyon
我会用代码更新我的问题。这有点长。 – Joey