我有一个方法,我传递一个“身份证”到这里:iOS应用崩溃:[__NSArrayI objectAtIndex:]:索引0超越界限的空数组
NSString *id = @"4bf58dd8d48988d181941735";
[self getNames:id];
这工作得很好,但是当我使用'从对象ID”通过SEGUE内:
NSString *id = _selectedStore._id;
[self getNames:id];
我得到的错误:
'NSRangeException', reason: '*** -[__NSArrayI objectAtIndex:]: index 0 beyond bounds for empty array'
这是怎么回事?
下面是它出现错误的地方。我的尝试(请记住我是新手)是取一个Foursquare ID的数组,获取名称,然后获取id的photoUrl。如果我删除所有创建photoUrl的代码(我已经在代码中注明),它会运行而不会崩溃。
- (void)getNames {
NSMutableArray *final = [[NSMutableArray alloc] init];
for (SearchVenue *object in self.venues) {
[Foursquare2 venueGetDetail:object._id callback:^(BOOL success, id result){
if (success) {
NSDictionary *dic = result;
NSArray *venue = [dic valueForKeyPath:@"response.venue"];
self.venueDetail = venue;
NSMutableDictionary *newVen = [NSMutableDictionary dictionary];
[newVen setValue:[self.venueDetail valueForKey:@"name"] forKey:@"name"];
[final addObject:newVen];
[Foursquare2 venueGetPhotos:object._id limit:nil offset:nil callback:^(BOOL success, id result){
if (success) {
NSDictionary *dic = result;
NSArray *photos = [dic valueForKeyPath:@"response.photos"];
self.venuePhotos = photos;
//works when removed from here...
NSString *prefix = [[self.venuePhotos valueForKeyPath:@"items.prefix"] objectAtIndex:0];
NSString *size = @"100x100";
NSString *suffix = [[self.venuePhotos valueForKeyPath:@"items.suffix"] objectAtIndex:0];
NSArray *myStrings = [NSArray arrayWithObjects:prefix,size,suffix, nil];
NSString *photoUrl = [myStrings componentsJoinedByString:@"" ];
//...to here
NSMutableDictionary *newVen1 = [NSMutableDictionary dictionary];
[newVen1 setValue:photoUrl forKey:@"photoUrl"];
for(int i = 0; i < [final count]; i++) {
[[final objectAtIndex:i] addEntriesFromDictionary:newVen1];
}
_arrayOfPlaces = final;
NSLog(@"_arrayOfPlaces is %@",_arrayOfPlaces);
[self.resultsVC reloadData];
} else {
NSLog(@"%@",result);
}
}];
} else {
NSLog(@"%@",result);
}
}];
}
}
在检查索引处的对象之前检查数组数量。 – Savitha 2014-12-02 06:20:05
“id”是Objective-C的内部生成关键字。你可以请尝试改变你的字符串名称valId或其他任何东西。 – Esha 2014-12-02 06:21:29
我将它改为'识别',但仍然出现错误。 – Ryasoh 2014-12-02 06:23:27