nginx - 解析后继续返回

Question

我想拒绝bingbot访问/ wp-admin和/wp-login.php，但我遇到了我的nginx配置问题。我开始与以下：

location ~ /(wp-admin|wp-login\.php) { 
    if ($http_user_agent ~* "(alltheweb|baidu|bingbot|googlebot|msnbot|slurp)") { 
     return 403; 
     break; 
    } 
} 

# Allow any php files to run 
location ~ \.php$ { 
    try_files $uri =404; 
    include /etc/nginx/fastcgi.conf; 
    fastcgi_pass unix:/var/lib/php/php.socket; 
} 

这只是正常的阻挡bingbot，但它也不会执行wp-login.php;它将它视为一个静态文件。我想：“好吧，你不通过下降到另外的场所块”，所以我复制的PHP代码到更高的一个：

location ~ /(wp-admin|wp-login\.php) { 
    if ($http_user_agent ~* "(alltheweb|baidu|bingbot|googlebot|msnbot|slurp)") { 
     return 403; 
     break; 
    } 
    location ~ \.php$ { 
     try_files $uri =404; 
     include /etc/nginx/fastcgi.conf; 
     fastcgi_pass unix:/var/lib/php/php.socket; 
    } 
} 

# Allow any php files to run 
location ~ \.php$ { 
    try_files $uri =404; 
    include /etc/nginx/fastcgi.conf; 
    fastcgi_pass unix:/var/lib/php/php.socket; 
} 

这使我再次登录，而不是下载wp-login.php，但现在bingbot是再次获得HTTP 200 OK！我如何有选择地返回403或PHP处理程序正确？

Answer 1

你可以尝试

if ($http_user_agent ~* "(alltheweb|baidu|bingbot|googlebot|msnbot|slurp)") { 
    location ~ /(wp-admin|wp-login\.php) { 
     return 403; 
    } 
} 

但是，您可能想设置这样的：

location /spider_blocked { 
    return 403; 
} 

if ($http_user_agent ~* "(alltheweb|baidu|bingbot|googlebot|msnbot|slurp)") { 
    rewrite ^/(wp-admin|wp-login\.php) /spider_blocked redirect; 
} 

基本上，你正在做的是建立了nginx的一个特殊的抓URL，做在特定用户代理访问的特定URL上重定向，并将其重定向到特殊的捕获URL以被阻止。