PHP MYSQL - 获取基于单个用户的等级（位置）的倍数行

Question

用下面的MySQL表：

+---------+-----------+ 
| user_id | user_name | 
+---------+-----------+ 
| 1 | user 1 | 
| 2 | user 2 | 
| 3 | user 3 | 
| 4 | user 4 | 
| 5 | user 5 | 
+---------+-----------+ 
+---------+-------------+ 
| user_id | user_staff | 
+---------+-------------+ 
| 1 | xxxxxx  | 
| 1 | xxxxxx  | 
| 2 | xxxxxx  | 
| 2 | xxxxxx  | 
| 2 | xxxxxx  | 
| 3 | xxxxxx  | 
| 3 | xxxxxx  | 
| 4 | xxxxxx  | 
+---------+-------------+ 

此查询得到我的排名表：

SELECT usr.user_name, COUNT(stf.user_id) AS score 
    FROM table_stafs AS stf 
    LEFT JOIN table_users AS usr ON usr.user_id=stf.user_id 
    GROUP BY usr.id 
    ORDER BY score DESC 

如何获得单个用户的位置？

Answer 1

您可以在查询结果中添加一个自动递增列，如果你想行列，例如：

SELECT usr.user_id,COUNT(stf.*) AS score, @r := @r + 1 AS rank 
FROM table_stafs AS stf, (SELECT @r := 0) a 
LEFT JOIN table_users AS usr ON usr.user_id=stf.user_id 
GROUP BY usr.id ORDER BY score DESC