抛出：IllegalArgumentException：u'Wrong FS：文件：//火花仓库，预计：文件：///”

Question

我试图用PySpark到我的Postgres数据库加载到星火：

from pyspark import SparkContext 
from pyspark import SparkConf 
from random import random 

#spark conf 
conf = SparkConf() 
conf.setMaster("spark://spark-master:7077") 
conf.setAppName('pyspark') 

sc = SparkContext(conf=conf) 

from pyspark.sql import SQLContext 
sqlContext = SQLContext(sc) 
properties = { 
    "user": "postgres", 
    "password": "password123", 
    "driver": "org.postgresql.Driver" 
} 
url = "jdbc.postgresql://<POSTGRES_IP>/DB_NAME" 
df = sqlContext.read.jdbc(url=url, table='myTable', properties=properties) 

我得到以下错误，我不知道它是什么意思。

/opt/spark/python/pyspark/sql/readwriter.pyc in jdbc(self, url, table, column, lowerBound, upperBound, numPartitions, predicates, properties) 
    420    jpredicates = utils.toJArray(gateway, gateway.jvm.java.lang.String, predicates) 
    421    return self._df(self._jreader.jdbc(url, table, jpredicates, jprop)) 
--> 422   return self._df(self._jreader.jdbc(url, table, jprop)) 
    423 
    424 

/usr/local/lib/python2.7/dist-packages/py4j/java_gateway.pyc in __call__(self, *args) 
    1131   answer = self.gateway_client.send_command(command) 
    1132   return_value = get_return_value(
-> 1133    answer, self.gateway_client, self.target_id, self.name) 
    1134 
    1135   for temp_arg in temp_args: 

/opt/spark/python/pyspark/sql/utils.pyc in deco(*a, **kw) 
    77     raise QueryExecutionException(s.split(': ', 1)[1], stackTrace) 
    78    if s.startswith('java.lang.IllegalArgumentException: '): 
---> 79     raise IllegalArgumentException(s.split(': ', 1)[1], stackTrace) 
    80    raise 
    81  return deco 

IllegalArgumentException: u'Wrong FS: file://spark-warehouse, expected: file:///' 

Answer 1

指定SQL仓库目录设置的现有目录应该可以解决您的问题。例如，在工作启动时间：

./bin/spark-submit --conf spark.sql.warehouse.dir=/tmp/ \ 
... # other options 
your_file.py \ 
[application-arguments]