2010-01-30 46 views
4

比方说,我有这个mysql table structureMySQL的返回表名

table : articles 
---------------- 
id 
content 

table : news 
------------ 
id 
news 

有没有办法来搜索这两个表一个字符串,然后如果发生字符串返回表的名称和行号?

回答

3

假设两个表有ID和新闻/内容相同的数据类型,然后沿

SELECT id, 'articles' as tablename 
WHERE content like '%string to search for%' 
UNION 
SELECT id, 'news' as tablename 
WHERE news like '%string to search for%' 

线路查询应该给你,你以后

+0

我只是猜测这里,但是从表名我想,他要搜索的字符串作为子串,而不是完全匹配。 – 2010-01-30 14:06:53

+0

yup,你是对的 – kmunky 2010-01-30 14:16:24

+0

@kmunky,改变它以符合你的确切要求:) – Rob 2010-01-30 14:32:09

1

你可以试试这个结果:

SELECT 'articles' as table_name, id 
FROM `articles` 
WHERE content like '%<my_string>%' 

UNION 

SELECT 'news' as table_name, id 
FROM `news` 
WHERE news like '%<my_string>%' 
+0

哼哼......想知道为什么我的回答得到了downvote?评论会有帮助! – 2010-01-30 19:17:14

1
SELECT * FROM (

SELECT id, content as text, 'articles' as tablename 
FROM articles 

UNION ALL 

SELECT id, news as text, 'news' as tablename 
FROM news 

) as tmp 

WHERE text = 'SEARCH_TERM' 
+1

MySql可能有点“非性能”(这是放置它的礼貌方式),所以以这种形式将两个表首先聚合在一起的查询可能比我自己和Cassy发布的版本慢。可悲的是,查询优化器并没有像Sql Server那样好 - ( – Rob 2010-01-30 14:37:17

+0

ya,你是对的。 – Rifat 2010-01-30 15:18:05