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Question

我试图使用dircmp功能蟒蛇来比较两个目录递归Python函数的返回值的简单列表

def cmpdirs(dir_cmp): 
    for sub_dcmp in dir_cmp.subdirs.values(): 
     cmpdirs(sub_dcmp) 
    return dir_cmp.left_only, dir_cmp.right_only, dir_cmp.common_files 

if __name__ == '__main__': 
    dcmp = dircmp('dir1', 'dir2') 
    result = list(cmpdirs(dcmp)) 

我试图得到这样一个结果：

([file1,file2],[file3,file4],[file5,file6]) 

这样做的最好方法是什么？

Answer 1

之前从未使用过dircmp ...但我认为这应该工作，寻找你的代码...

def cmpdirs(dir_cmp): 
    # make copies of the comparison results 
    left = dir_cmp.left_only[:] 
    right = dir_cmp.righ_only[:] 
    common = dir_cmp.common_files[:] 

    for sub_dcmp in dir_cmp.subdirs.values(): 
     sub_left, sub_right, sub_common = cmpdirs(sub_dcmp) 

     # join the childrens results 
     left += sub_left 
     right += sub_right 
     common += sub_common 

    # return the merged results 
    return (left, right, common) 

if __name__ == '__main__': 
    dcmp = dircmp('dir1', 'dir2') 
    result = cmpdirs(dcmp)