如何在不重新加载页面的情况下使用ASP.NET MVC 5将数据导出到Excel？

Question

将数据导出到Excel的过程正在运行。但我不需要重新加载页面。当我尝试按导出数据到Excel页面正在重新加载。如何避免这种情况？请帮忙。谢谢。

C＃：

public ActionResult Export(int id) { 
    Excel.Application application = new Excel.Application(); 
    Excel.Workbook workbook = application.Workbooks.Add(System.Reflection.Missing.Value); 
    Excel.Worksheet worksheet = workbook.ActiveSheet; 
    var export = _context.Employees.Where(x => x.Id == id)ToList(); 

    worksheet.Cells[1, 1] = "Name"; 
    worksheet.Cells[1, 2] = "Age"; 
    worksheet.Cells[1, 3] = "Position"; 
    worksheet.Cells[1, 4] = "Address"; 
    worksheet.Cells[1, 5] = "Contact"; 

    foreach (var e in export) 
    { 
     worksheet.Cells[row, 1] = e.Name; 
     worksheet.Cells[row, 2] = e.Age; 
     worksheet.Cells[row, 3] = e.Position; 
     worksheet.Cells[row, 4] = e.Address; 
     worksheet.Cells[row, 5] = e.Contact; 

     row++; 
    } 

    workbook.SaveAs(@"C:\Excel\sample.xls"); 
    workbook.Close(); 
    Marshal.ReleaseComObject(workbook); 

    application.Quit(); 
    Marshal.FinalReleaseComObject(application); 

    return View(); 
} 

阿贾克斯：

<script> 
    $(document).ready(function() { 
     $(".js-export").click(function(e) { 
      var link = $(e.target); 
      $.ajax({ 
        url: "/home/export/" + link.attr("data-export-id"), 
        method: "GET" 
        }) 
     }); 
    }); 
</script> 

事件：

<a href="#" class="js-export btn btn-danger btn-xs" data-export-id="@item.Id">Export to Excel</a> 

Answer 1

而不是使用的ActionResult可以使用JsonResult并且可以返回Excel文件的唯一网址： -

$.ajax({ 
      type: 'GET', 
      url: "/home/export/" + link.attr("data-export-id"), 
      dataType: 'json',     
      success: function (data) {     
       console.log(data.ExcelUrl); 
      } 
     }); 

你在控制器代码： -

public JsonResult Export(int id) 
     { 
      //Exel generation code here showing in your post. 
      return Json(new { ExcelUrl = "New Excel URL path" }, JsonRequestBehavior.AllowGet); 
     } 

Answer 2

呼叫通过$.ajax的行动，并在行动返回FileResult：

public FileResult Export(int id) 
{ 
    //.........your file creation logic goes here ....// 

    byte[] fileBytes = File.ReadAllBytes(filePath); 
    return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, fileName); 
}