2016-11-28 421 views
1

我有一个Python执行器,它解决了2个函数,即get_tech_courses()get_music_courses()返回单个列表; 1和2。Python - 将两个列表组合成一个json对象

清单1.

[ 
{'title': 'THE COMPLETE PYTHON WEB COURSE', 'downloads': '4', 'views': '88'}, 
{'title': 'THE COMPLETE JAVA WEB COURSE', 'downloads': '16', 'views': '156'} 
] 

清单2.

[ 
{'title': 'THE COMPLETE GUITAR COURSE', 'downloads': '18', 'views': '125'}, 
{'title': 'THE COMPLETE KEYBOARD COURSE', 'downloads': '63', 'views': '98'} 
] 

我想无论是列出了一个JSON数组父,courses这样的捆绑下的结合:

{"courses": 
[{'title': 'THE COMPLETE PYTHON WEB COURSE', 'downloads': '4', 'views': '88'}, 

{'title': 'THE COMPLETE JAVA WEB COURSE', 'downloads': '16', 'views': '156'}, 

{'title': 'THE COMPLETE GUITAR COURSE', 'downloads': '18', 'views': '125'}, 

{'title': 'THE COMPLETE KEYBOARD COURSE', 'downloads': '63', 'views': '98'}] 
} 


这不是打印正确的json。

from concurrent.futures import ThreadPoolExecutor 

import tech_course 
import music_course 
import json 

courses = [] 

with ThreadPoolExecutor(max_workers=2) as executor: 
    courses.append(executor.submit(tech_course.get_tech_course).result()) 
    courses.append(executor.submit(music_course.get_music_course).result()) 

print(json.dumps(courses)) 
+2

什么:'combined_lists = { “课程”:列表1 +列表2}'。这不是你想要的吗? – edgarstack

回答

4

尝试以下操作:

import json 

list_1 = [ 
    {'title': 'THE COMPLETE PYTHON WEB COURSE', 'downloads': '4', 'views': '88'}, 
    {'title': 'THE COMPLETE JAVA WEB COURSE', 'downloads': '16', 'views': '156'}] 

list_2 = [ 
    {'title': 'THE COMPLETE GUITAR COURSE', 'downloads': '18', 'views': '125'}, 
    {'title': 'THE COMPLETE KEYBOARD COURSE', 'downloads': '63', 'views': '98'}] 

res_dict = {"courses": list_1 + list_2 } 

to_json = json.dumps(res_dict) 

输出:

>>> to_json 
'{"courses": [{"downloads": "4", "views": "88", "title": "THE COMPLETE PYTHON WEB COURSE"}, {"downloads": "16", "views": "156", "title": "THE COMPLETE JAVA WEB COURSE"}, {"downloads": "18", "views": "125", "title": "THE COMPLETE GUITAR COURSE"}, {"downloads": "63", "views": "98", "title": "THE COMPLETE KEYBOARD COURSE"}]}' 
+0

在我的问题中,我将执行者的结果附加到'courses'列表中。我们可以这样做吗? – CodeWalker

+0

如果课程是一个列表,并且您想要添加到其他列表的元素,则需要使用'extend'而不是'append' – ettanany

+0

工作!干杯。 – CodeWalker