nextLine（）不能正常工作..（Java）

Question

我做了一个名为“Skill”的对象和主程序。 技能：

import java.util.*; 
class Skill 
{ 
    static Scanner reader = new Scanner(System.in); 
    public int iStar; 
    public int iColor; //0-White, 1-Red, 2-Orange, 3-Grenn, 4-DeepSkyBlue, 5-Blue. 
    public String sName; 
    public String sText; 
    public String sLink; 
    public String sRank; 
    Skill() 
    { 
     System.out.println ("What is the skill name?"); 
     this.sName = reader.nextLine(); 
     System.out.println ("Insert the icon's link please"); 
     this.sLink = reader.nextLine(); 
     System.out.println ("Which rank is recommended to this skill?"); 
     this.sRank = reader.nextLine(); 
     System.out.println ("Explanation about the skill"); 
     this.sText = reader.nextLine(); 
     System.out.println ("Text color?" + "\n" + "1-Red, 2-Orange, 3-Green, 4-DeepSkyBlue, 5-Blue."); 
     this.iColor = reader.nextInt(); 
     System.out.println ("How many stars would you like? (0-2)"); 
     this.iStar = reader.nextInt(); 
    } 
    void FixMe () 
    { 
     int iNum = 0; 
     System.out.println ("Which one of the data would you like to change?" + "\n" + "0-non of them, 1-Star, 2-Color, 3-Name, 4-Text, 5-Link, 6-Rank."); 
     do 
     { 
      switch (reader.nextInt()) 
      { 
       case 0: iNum = 0; 
           break; 
       case 1: this.iStar = reader.nextInt(); 
           iNum = 0; 
           break; 
       case 2: this.iColor = reader.nextInt(); 
           iNum = 0; 
           break; 
       case 3: this.sName = reader.nextLine(); 
           iNum = 0; 
           break; 
       case 4: this.sText = reader.nextLine(); 
           iNum = 0; 
           break; 
       case 5: this.sLink = reader.nextLine(); 
           iNum = 0; 
           break; 
       case 6: this.sRank = reader.nextLine(); 
           iNum = 0; 
           break; 
       default: System.out.println ("Error, Please insert again the number of the data (!) ."); 
            iNum = 1; 
            break; 
      } 
     } 
     while (iNum == 1); 
    } 
    String ImageIt () 
    { 
     String sPro = "[IMG]" + this.sLink + "[/IMG]"; 
     return sPro; 
    } 
    String BoldIt () 
    { 
     String sPro = "[B]Rank " + this.sRank + "[/B]"; 
     return sPro; 
    } 
    String UnderscoreIt () 
    { 
     String sPro = "[U]" + this.sName + "[/U]"; 
     return sPro; 
    } 
    String ColorIt (String sNoob) 
    { 
     String sPro = "[COLOR=\""; 
     int iNum = 0; 
     do 
     { 
      switch (this.iColor) 
      { 
       case 1: sPro+= "Red"; 
           iNum = 0; 
           break; 
       case 2: sPro+= "Orange"; 
           iNum = 0; 
           break; 
       case 3: sPro+= "Green"; 
           iNum = 0; 
           break; 
       case 4: sPro+= "DeepSkyBlue"; 
           iNum = 0; 
           break; 
       case 5: sPro+= "Blue"; 
           iNum = 0; 
           break; 
       default: System.out.println ("Error, Please insert again the number of the color (!) ."); 
            this.iColor = reader.nextInt(); 
            iNum = 1; 
            break; 
      } 
     } 
     while (iNum == 1); 
     sPro+= "\"]" + sNoob + "[/COLOR]"; 
     return sPro; 
    } 
    String WhiteColorIt (int FirstOrSecond) 
    { 
     String sPro = "[COLOR=\"White\"]"; 
     if (FirstOrSecond == 1) 
     { 
      int iNum = 0; 
      do 
      { 
       if (this.iStar >= 3 || this.iStar < 0) 
       { 
        System.out.println ("Error, Please insert again the number of the stars (!) ."); 
        this.iStar = reader.nextInt(); 
        iNum = 1; 
       } 
       else 
       { 
        iNum = 0; 
       } 
      } 
      while (iNum == 1); 
      iNum = 2 - this.iStar; 
      for (; iNum != 0; iNum--) 
       sPro+= "*"; 
      sPro+= "[/COLOR]"; 
     } 
     else 
      sPro+= "**[/COLOR]"; 
     return sPro; 
    } 
    /*הפעולה הראשית*/ 
    String ExtractMe() 
    { 
     String sPro = ""; 
     String sTemp = ""; 
     switch (this.iStar) 
     { 
      case 0: sPro+= this.WhiteColorIt (2) + " "; 
          sTemp = this.ImageIt() + " " + this.UnderscoreIt(); 
          sTemp = this.ColorIt (sTemp); 
          sPro+= sTemp; 
          break; 
      case 1: sPro+= this.WhiteColorIt (1); 
          sTemp = "* " + this.ImageIt() + " " + this.UnderscoreIt(); 
          sTemp = this.ColorIt (sTemp); 
          sPro+= sTemp; 
          break; 
      case 2: sPro+= "** " + this.ImageIt() + " " + this.UnderscoreIt(); 
          sPro = this.ColorIt (sPro); 
          break; 
      default: 
           break; 
     } 
     sPro+= " - " + this.sText + "\n"; 
     sPro+= this.WhiteColorIt (2) + " " + this.BoldIt() + "."; 
     return sPro; 
    } 
} 

主营：

import java.util.*; 
public class Main 
{ 
    static Scanner reader = new Scanner(System.in); 
    public static void main(String[] args) 
    { 
     String sPro = ""; 
     Skill Winner01 = new Skill(); 
     System.out.println ("האם אתה רוצה לתקן את אחד הנתונים?" + "\n" + "1-Yes, 2-No"); 
     if (reader.nextInt() == 1) 
       Winner01.FixMe(); 
     sPro+= Winner01.ExtractMe() + "\n"; 
     Skill Winner02 = new Skill(); 
     System.out.println ("האם אתה רוצה לתקן את אחד הנתונים?" + "\n" + "1-Yes, 2-No"); 
     if (reader.nextInt() == 1) 
       Winner02.FixMe(); 
     sPro+= Winner02.ExtractMe() + "\n"; 
     System.out.println (sPro); 
    } 
} 

我使用BlueJ的，虽然我试图测试程序我犯了2个技能。所以我使用了两次“Skill（）”，但是第二次，reader.nextLine（）不起作用。

Answer 1

您正在创建扫描仪类的两个实例，均附于System.in。一个坐在你的课Main班，另一个坐在Skill班。当他们尝试从相同的输入流中读取时，这两者会发生干扰。

一个可能的解决方案是仅实例化一个扫描器并将其作为参数传递给您的Skill类的构造函数。 'nextLine（）`不能正常工作的方式？