2
因此,我从网上转移我的实例,下载了一个安装它的密钥对,一切都运行良好大约一天。然后我重新启动了我的电脑,并且无法再通过SSH连接。我尝试redownloading一个密钥对并重新安装它,但我不断获得权限被拒绝(publickey)错误。无法SSH进入EC2实例
debug1: Reading configuration data /etc/ssh_config
debug1: Applying options for *
debug1: Connecting to ec2-184-73-218-40.compute-1.amazonaws.com [184.73.218.40] port 22.
debug1: Connection established.
debug1: identity file /Users/tigger/.ec2/domainpolish type 1
debug1: identity file /Users/tigger/.ec2/domainpolish-cert type -1
debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3p1 Debian-3ubuntu7
debug1: match: OpenSSH_5.3p1 Debian-3ubuntu7 pat OpenSSH*
debug1: Enabling compatibility mode for protocol 2.0
debug1: Local version string SSH-2.0-OpenSSH_5.6
debug1: SSH2_MSG_KEXINIT sent
debug1: SSH2_MSG_KEXINIT received
debug1: kex: server->client aes128-ctr hmac-md5 none
debug1: kex: client->server aes128-ctr hmac-md5 none
debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent
debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP
debug1: SSH2_MSG_KEX_DH_GEX_INIT sent
debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY
debug1: Host 'ec2-184-73-218-40.compute-1.amazonaws.com' is known and matches the RSA host key.
debug1: Found key in /Users/tigger/.ssh/known_hosts:11
debug1: ssh_rsa_verify: signature correct
debug1: SSH2_MSG_NEWKEYS sent
debug1: expecting SSH2_MSG_NEWKEYS
debug1: SSH2_MSG_NEWKEYS received
debug1: Roaming not allowed by server
debug1: SSH2_MSG_SERVICE_REQUEST sent
debug1: SSH2_MSG_SERVICE_ACCEPT received
debug1: Authentications that can continue: publickey
debug1: Next authentication method: publickey
debug1: Offering RSA public key: /Users/tigger/.ec2/domainpolish
debug1: Authentications that can continue: publickey
debug1: Offering RSA public key: domainpolish
debug1: Authentications that can continue: publickey
debug1: No more authentication methods to try.
Permission denied (publickey).
我也试图重新启动实例:
这是详细输出(我使用-i /路径/到/密钥对的选项,以及没有运气尝试)。任何人都可以尝试其他任何东西?非常感谢!
我会在亚马逊论坛上发布相同的内容:https://forums.aws.amazon.com/forum.jspa?forumID=30 AWS员工有一个绝招,即绝大多数SO用户不会:他们可以看到发生了什么事。 :) – Iterator
&然后如果你得到答案,请回答在答案部分它可能是很好的帮助。 –