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我正计划在Firebase服务收到消息时启动通知，但通知触发两次（一次，第二次可能30分钟后）触发的问题是我的代码：Firebase onMessageReceived会触发两次
sharedPreferences = PreferenceManager
.getDefaultSharedPreferences(getApplicationContext());
// Check if message contains a data payload.
if (remoteMessage.getData().size() > 0) {
Intent myIntent = new Intent(MyFirebaseMessagingService.this, MyAlarmService.class);
pendingIntent = PendingIntent.getService(MyFirebaseMessagingService.this, 0, myIntent, 0);
AlarmManager alarmManager = (AlarmManager)getSystemService(ALARM_SERVICE);
long currentTime = System.currentTimeMillis();
int hour=sharedPreferences.getInt("Hour",9);
int min=sharedPreferences.getInt("Min",0);
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.HOUR_OF_DAY,hour);
calendar.set(Calendar.MINUTE,min);
alarmManager.set(AlarmManager.RTC_WAKEUP,calendar.getTimeInMillis() , pendingIntent);
这是MyAlarmService onStartCommand：
public int onStartCommand(Intent intent, int flags, int startId) {
Uri uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(this);
mBuilder.setSmallIcon(R.mipmap.ic_launcher);
mBuilder.setContentTitle("Figures");
mBuilder.setContentText("New Figures has been updated!");
mBuilder.setAutoCancel(true);
mBuilder.setSound(uri);
Intent resultIntent = new Intent(this, LoginActivity.class);
TaskStackBuilder stackBuilder = TaskStackBuilder.create(this);
stackBuilder.addParentStack(LoginActivity.class);
stackBuilder.addNextIntent(resultIntent);
PendingIntent resultPendingIntent = stackBuilder.getPendingIntent(0, PendingIntent.FLAG_UPDATE_CURRENT);
mBuilder.setContentIntent(resultPendingIntent);
NotificationManager mNotificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
mNotificationManager.notify(0, mBuilder.build());
return super.onStartCommand(intent, flags, startId);
}
这里是Vb.net发送通知功能：
Private Function sendNotification() As Integer
Try
Dim url As String = "https://fcm.googleapis.com/fcm/send"
Dim tRequest As WebRequest = WebRequest.Create(url)
tRequest.Method = "post"
tRequest.ContentType = "application/json"
Dim data = New With { _
Key .[to] =myTopic, _
Key .TTL = "109", _
Key .data = New With { _
Key .body = "Updated", _
Key .title = "Daily" _
} _
}
Dim jssons As String = Newtonsoft.Json.JsonConvert.SerializeObject(data)
Dim bytearray As Byte() = Encoding.UTF8.GetBytes(jssons)
tRequest.Headers.Add(String.Format("Authorization: key={0}", MyKey))
tRequest.Headers.Add(String.Format("Sender: id={0}", MySenderId))
tRequest.ContentLength = bytearray.Length
tRequest.ContentType = "application/json"
Using datastream As Stream = tRequest.GetRequestStream()
datastream.Write(bytearray, 0, bytearray.Length)
Using tresponse As WebResponse = tRequest.GetResponse
Using dataStreamResponse As Stream = tresponse.GetResponseStream()
Using tReader As StreamReader = New StreamReader(dataStreamResponse)
Dim sResponseFromServer As String = tReader.ReadToEnd()
Log(sResponseFromServer, w)
End Using
End Using
End Using
End Using
Catch ex As WebException
Log(ex.Message, w)
Return ex.Status
End Try
Log("Notification sent", w)
Return 200
End Function
有没有更好的方式发送通知？，AlarmManager中是否有任何问题？ 谢谢。